Please help. solve for the variable

Mathematics

1 answer:

Elanso [62]3 years ago

4 0

Answer:

Step-by-step explanation:

12. 6(5n-3)=36n

-divide each side by six: 5n-3=6n

-subtract 5n from 6n: n= -3

14. 5b+8/3=3b

-multiply each side by 3: 5b+8=9b

-subtract 5b from 9b: 8=4b

-divide each side by 4: b=2

16. 3r+4-8r=4r-12

-subtract 3r-8r= 5r: 5r+4=4r-12

-Subtract 4r from 5r, then subtract 4 from 12

r = -16

You might be interested in

Y=6x/5 +27 find y-intercept and slope

mixas84 [53]

Answer:

General equation of a line is given by y = mx +c, where m is the gradient /slope, c is the intercept. To find for the intercept on y- axis, put x = 0.
$y = \frac{6(0)}{5 } + 27 \\ y = \frac{0}{5} + 27 \\ y = 27 \\ therefore \: the \: intercept \: on \: y \: is \: 27 \\$
By comparison,
$y = mx + \: c \\ y = \frac{6}{5} x \: +27 \\ m = \frac{6}{5 \: } \: \\ hence \: slope \: is \: \frac{6}{5}$

5 0

2 years ago

A string of decorative lights is 25 feet long. The first light on the string is 16 inches from the plug. The lights on the strin

joja [24]

25 feet = 25 x 12 = 300 inches

First light is at 16 inches.
300 - 16 = 284 inches

Find the rest of the bulbs:
284 ÷ 4 = 71

Total number of lights = 71 + 1 = 72

Answer 72 lights

8 0

2 years ago

Given that (6 3) is on the graph of f(x) find the corresponding point for the function f(-1/2x)

Vlada [557]

$\bf \begin{array}{rllll}
(6&,&3)&f(x)\\
x&&y\\\\
(-\frac{1}{2}x&,&3)&f(-\frac{1}{2}x)\\\\
(-\frac{1}{2}\cdot 6&,&3)\\\\
(-3&,&3)
\end{array}$

keep in mind that, a negative coefficient to "x", will make the graph reflect over the y-axis.

6 0

3 years ago

Read 2 more answers

Which ones correct?

natima [27]

Answer:

Step-by-step explanation:

y = 4 is a horizontal line which would be parallel to the x axis

6 0

2 years ago

Can someone help me please

NikAS [45]