Answer:
A, both can be sides of a triangle
Step-by-step explanation:
- you add up the lowest side lengths and see if they are more than the largest side length
- if they are then they can be side lengths
<span>√x^2+2x-10=√x+20
raising both members to the square
</span> x^2+2x-10=x+20
rewriting
x^2+x-30=0
factoring
(x+6)(x-5)=0
therefore the solutions are
<span> x = –6, x = 5
</span>the answer is
<span>B. x = –6, x = 5</span>
A. The centre of the circle is: (-5, 8)
3x+2y=6
(2,3)
x intercept = 2 y intercept = 3