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Alecsey [184]
3 years ago
15

A consumer organization estimates that 35% of the households in a particular community have one television set, 39% have two set

s, and 16% have three or more sets. If two independent households are chosen at random, what is the probability that at least one has one or more television sets
Mathematics
1 answer:
nikitadnepr [17]3 years ago
5 0

Answer:

90%

Step-by-step explanation:

Probability of households with one TV = 35% or 0.35

Probability of households with two sets = 39% or 0.39

Probability of households with three or more = 16% or 0.16

The probability of a household with no TV set = 0.10 or 10% (1 - 0.35 - 0.39 - 0.16)

Therefore, the probability of a household with at least one or more sets = 90% (35% + 39% + 16%) or 100% - 10%.

Probability is the chance that something may occur out of many events.  To calculate probability, we divide the number of events by the number of possible outcomes.

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Answer:½((n/2) – ½) – ½ = 10

½(n/2) – ¼ - ½ = 10 (using the distributive property)

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Step-by-step explanation:

Let’s start by writing Josie’s first step as an expression. Dividing n by 2, then subtracting ½ from

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<h3>How to reflect a point across an axis?</h3>

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