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SashulF [63]
3 years ago
5

What are the diameters of the painting? Easy!!!

Mathematics
1 answer:
zalisa [80]3 years ago
7 0

x = 10.22 in

Solution:

Width of the figure = x in

Length of the figure = (2x + 5) in

Area of the figure = 260 in²

<u>To find the value of x:</u>

<em>Area of the figure = length × width</em>

length × width = 260

(2x + 5) × x = 260

2x^2+5x=260

Subtract 260 from both sides of the equation.

2x^2+5x-260=0

Factor the above quadratic expression.

Quadratic equation formula:

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

$x=\frac{-5 \pm \sqrt{5^{2}-4 \cdot 2(-260)}}{2 \cdot 2}

$x=\frac{-5 \pm \sqrt{2105}}{4}

$x=\frac{-5+\sqrt{2105}}{4}, \  x=\frac{-5-\sqrt{2105}}{4}

x = 10.22,   x = –12.72006

Dimension of the figure cannot be measured in negative terms.

Hence x = 10.22 in.

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