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Mazyrski [523]
4 years ago
15

A fashion designer wants to know how many new dresses women buy each year. Assume a previous study found the standard deviation

to be 1.2. She thinks the mean is 7.9 dresses per year. What is the minimum sample size required to ensure that the estimate has an error of at most 0.12 at the 90% level of confidence? Round your answer up to the next integer.
Mathematics
1 answer:
NemiM [27]4 years ago
4 0

Answer:

Atleast 271

Step-by-step explanation:

Given that a  fashion designer wants to know how many new dresses women buy each year. Assume a previous study found the standard deviation to be 1.2.

Mean =7.9

For margin error to be at most 0.12

we have for 90% confidence level

1.645*\frac{1.2}{\sqrt{n} } \leq 0.12\\\sqrt{n}\geq 16.45\\n\geq 270.6\\n\geq 271

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Hailey sold 20 tickets to the school play for a total of 225$.Early bird tickets were 10$ and regular priced tickets were 15$.Wr
dlinn [17]

Answer:

The system of equation are \left \{ x+y=20} \atop {10x+15y=225}} \right.

The number of early bird tickets are <u>15</u> and of regular tickets are <u>5</u>.

Step-by-step explanation:

Given,

Total number of tickets = 20

Total amount = $225

Solution,

Let the number of early bird tickets be 'x'.

And also let the number of regular tickets be 'y'.

Now total number of tickets is the sum of number of early bird tickets and number of regular tickets.

So framing in equation form, we get;

Total number of tickets = number of early bird tickets + number of regular tickets

x+y=20\ \ \ \ equation\ 1

Again, Total amount is the sum of number of early bird tickets multiplied with price of each ticket and number of regular tickets multiplied with price of each ticket.

So framing in equation form, we get;

10x+15y=225\ \ \ \ \ equation\ 2

Hence the system of equation are \left \{ x+y=20} \atop {10x+15y=225}} \right.

Now we solve the equation by multiplying equation 1 by 10, and get;

10(x+y)=20\times10\\\\10x+10y=200\ \ \ \ equation\ 3

Now subtracting equation 3 from equation 2, we get;

(10x+15y)-(10x+10y)=225-200\\\\10x+15y-10x-10y=25\\\\5y=25\\\\y=\frac{25}{5}=5

On substituting the value of 'y' in equation 1, we get;

x+y=20\\\\x+5=20\\\\x=20-5=15

Hence The number of early bird tickets are <u>15</u> and of regular tickets are <u>5</u>.

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