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xxMikexx [17]
3 years ago
6

Please help me w/H.W please show the work​

Mathematics
2 answers:
Oliga [24]3 years ago
8 0

Answer:

1).   (3² - 4²) = 29

2).  5a - 7b + b² = -15

Step-by-step explanation:

Points to remember

1) (a² - b²) = (a + b) (a - b)

<u>Solve 22 - (3² - 4²)</u>

To find (3² - 4²)

(3² - 4²) can be written as,

(3² - 4²) = (3 + 4 ) (3 - 4) = 7 * -1 = -7

22 - (3² - 4²)  = 22 - (-7) = 22 + 7 = 29

22 - (3² - 4²) = 29

<u>To solve 5a - 7b + b²for a = -1 and b= 5</u>

Substitute the value of a and b in given expression we get,

5a - 7b + b² = (5 * -1) - (7 * 5) + 5²

= -5 - 35  + 25 = -15

Therefore 5a - 7b + b² = -15

monitta3 years ago
3 0

1) 29

2) -15

//Hope this helps.

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The length of a rectangle field is represented by the expression 14 X minus 3X squared +2 Y. The width of the field is represent
Assoli18 [71]

Answer:

9x+4x^2-5y

Step-by-step explanation:

Hi there!

Length of the field: 14x-3x^2+2y units

Width of the field: 5x-7x^2+7y units

To find how much greater the length of the field is than the width, subtract the width from the length:

14x-3x^2+2y-(5x-7x^2+7y)

Open up the parentheses

= 14x-3x^2+2y-5x+7x^2-7y

Combine like terms

= 14x-5x-3x^2+7x^2+2y-7y\\= 9x+4x^2-5y

Therefore, the length is 9x+4x^2-5y units greater than the width.

I hope this helps!

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2 years ago
What are all the steps to solving a Quadratic Formula? (steps please)
nika2105 [10]

Compose the quadratic condition in standard shape, ax2 + bx + c = 0. Recognize the values of a, b, c. Write the Quadratic Equation. At that point substitute within the values of a, b, c. Simplify. Check the arrangements.

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Which statement must be true to be able to use the AAS Congruence Theorem to prove triangle LMN is congruent to triangle PON?
aev [14]

Answer:

a

Step-by-step explanation:

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3 years ago
Help me help 2 tries only
Alborosie

Answer:

2,637,070

Step-by-step explanation:

2891+66= 2963

2963x 890= 2,637,070

Correction

890+ 66= 956

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Answer:

i believe its 2

Step-by-step explanation:

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