All categories

2 years ago

Please help me w/H.W please show the work

Mathematics

2 answers:

Oliga [24]2 years ago

8 0

Answer:

1). (3² - 4²) = 29

2). 5a - 7b + b² = -15

Step-by-step explanation:

Points to remember

1) (a² - b²) = (a + b) (a - b)

Solve 22 - (3² - 4²)

To find (3² - 4²)

(3² - 4²) can be written as,

(3² - 4²) = (3 + 4 ) (3 - 4) = 7 * -1 = -7

22 - (3² - 4²) = 22 - (-7) = 22 + 7 = 29

22 - (3² - 4²) = 29

To solve 5a - 7b + b²for a = -1 and b= 5

Substitute the value of a and b in given expression we get,

5a - 7b + b² = (5 * -1) - (7 * 5) + 5²

= -5 - 35 + 25 = -15

Therefore 5a - 7b + b² = -15

monitta2 years ago

3 0

1) 29

2) -15

//Hope this helps.

You might be interested in

Find f-1(x) when f(x) = 3x + 2.

vladimir2022 [97]

I hope this helps you

7 0

3 years ago

In 1985, there were 285 cell phone subscribers in Arlington. The number of subscribers increased by 75% per year since 1985. Fin

ANTONII [103]

Answer:

The number of subscribers in 2008 is 110,845,988

Step-by-step explanation:

The number of cell phone subscribers in Arlington, in t years after 1985, can be modeled by the following equation.

$N(t) = N(0)(1+r)^{t}$

And which N(0) is the number of subscribers in 1985 and r is the rate it increases per year, as a decimal.

In 1985, there were 285 cell phone subscribers in Arlington.

This means that $N(0) = 285$

The number of subscribers increased by 75% per year since 1985.

This means that $r = 0.75$

$N(t) = 285(1.75)^{t}$

Find the number of subscribers in 2008.

2008 is 2008-1985 = 23 years after 1985. So we have to find N(23).

$N(23) = 285(1.75)^{23} = 110,845,988$

The number of subscribers in 2008 is 110,845,988

8 0

3 years ago

The average performance rating of the employees at Company A is 6.5 on a scale from 1 to 10 (10 being highest). The standard dev

djyliett [7]

Answer:

The best choice would be hiring a random employee from company A

Step-by-step explanation:

Supposing that the performance rating of employees follow approximately a normal distribution on both companies, we are interested in finding what percentage of employees of each company have a performance rating greater than 5.5 (which is the mean of the scale), when we measure them in terms of z-scores.

In order to do that we standardize the scores of both companies with respect to the mean 5.5 of ratings

The z-value corresponding to company A is

$z=\frac{\bar x-\mu}{s}$

where

$\bar x$ = mean of company A

$\mu$ = 5.5 (average of rating between 1 and 10)

s = standard deviation of company A

$z=\frac{\bar x-\mu}{s}=\frac{6.5-5.5}{2.1}=0.7142$

We do the same for company C

$z=\frac{\bar x-\mu}{s}=\frac{7.4-5.5}{6.8}=0.2794$

This means that 27.49% of employees of company C have a performance rating > 5.5, whereas 71.42% of employees of company B have a performance rating > 5.5.

So, the best choice would be hiring a random employee from company A

4 0

3 years ago

Tyler used 1 and 1/4 gallons of paint to paint 5/7 of a fence. How many gallons will it take to paint the whole fence? Select th

Tanzania [10]

Answer:

The correct answer is the first one, 1 and 1/4 divided by 5/7 = ?

Step-by-step explanation:

There's not much else to it.

It's just the answer that makes the most sense.

Just use the elimination sequence.

I hope this helps!

7 0

3 years ago

What is $22 marked up to $33

Kitty [74]

What is $22 marked up to $33
Ok, let us first analyze the given problem.
=> 22 dollars is said to be the original amount of money.
=> 33 dollars is the total marked up amount.
Now, we need to find out how many percent did the money increased
Solutions:
=> 33 dollars - 22 dollars = 11 dollars
=> 11 dollars / 22 dollars = 0.5 dollars
=> 0.5 dollars * 100% = 50%
Thus, the marked up money is 50%

7 0

3 years ago

Read 2 more answers

Please help me w/H.W please show the work​

Please help me w/H.W please show the work