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3 years ago

Y2 + 8zx - 2xy -4yz factorise ?

Mathematics

1 answer:

Rainbow [258]3 years ago

4 0

$y^2+8zx-2xy-4yz=(y^2-2xy)+(8xz-4yz)\\\\=y(y-2x)-4z(-2x+y)=y(y-2)-4z(y-2x)\\\\=\boxed{(y-2x)(y-4z)}$

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There are 8 girls for every 7 boys on a field trip.if there 56 girls on the trip how many students are on the trip

Ket [755]

Well the first thing you need to do is set up a proportion.

8 girls 56 girls

-------- = -----------

7 boys x

Now what we have to do is find out what we multiplied by 8 to get 56.

Simply divide.

56 ÷ 8 = 7

So, we figured out that the magic number is 7!

So we multiply the boy number by 7

7 x 7 = 49

So this means that there are 49 boys on the field trip.

8 0

3 years ago

∆ABC transforms to produce ∆A'B'C'. Which transformation did NOT take place?

melisa1 [442]

Answer:

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Step-by-step explanation:

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3 years ago

Write an algebraic expression for the phrase the product of 4 and s.

notka56 [123]

Answer: 4s

Step-by-step explanation:

Product means multiply

4 times s = 4s

8 0

3 years ago

Read 2 more answers

Find (fºg)(1) f(x) = x² - 1 g(x) = √x A.0 B.1 C.4 √2 D. √8

Savatey [412]

Given:

The function are

$f(x)=x^2-1$

$g(x)=\sqrt{x}$

To find:

The value of $(f\circ g)(1)$ .

Solution:

We have,

$f(x)=x^2-1$

$g(x)=\sqrt{x}$

We need to find the value of $(f\circ g)(1)$ .

$(f\circ g)(1)=f(g(1))$ $[\because (f\circ g)(x)=f(g(x))]$

$(f\circ g)(1)=f(\sqrt{1})$ $[\because g(x)=\sqrt{x}]$

$(f\circ g)(1)=f(1)$

$(f\circ g)(1)=(1)^2-1$ $[\because f(x)=x^2-1]$

$(f\circ g)(1)=1-1$

$(f\circ g)(1)=0$

The value of $(f\circ g)(1)$ is 0.

Therefore, the correct option is A.

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3 years ago

Plz will gave a brain who ever answer this will get a brain

inessss [21]

Energy in the form of HEAT

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3 years ago