Answer:
Options c and d
Step-by-step explanation:
Given is a graph with period pi.
ii) The graph is discontinuous
iii) x intercepts are say (a) units to the right of y axis and repeats for every interval of pi.
Fix the function
a) y = sinx cannot be this graph because sinx is a continuous graph
b) y =cosx cannot be this graph because cosx is a continuous graph
e) y = sec x is undefined for the range (-1,1) since the given graph is defined in this interval, secx is not answer.
f)y = csc x is undefined for the range (-1,1) since the given graph is defined in this interval, cscx is not answer.
c) y=tanx is a discontinuous graph at x = odd multiples of pi/2
Hence the given graph can be of the form y =- tan (2x+a) which shows reflection over y axis,
d) y = cotx can also be this graph with adjustments for period and horizontal shift.
So answers are c and d
Answer:
The option "StartFraction negative 2 (x + 6) Over (x + 4) (x minus 4) EndFraction" is correct
That is 
Therefore 
Step-by-step explanation:
Given problem is StartFraction x Over x squared minus 16 EndFraction minus StartFraction 3 Over x minus 4 EndFraction
It can be written as below :

To solve the given expression


( using the property
)

( by using distributive property )



Therefore 
Therefore the option "StartFraction negative 2 (x + 6) Over (x + 4) (x minus 4) EndFraction" is correct
That is 
Answer:
Not True
Step-by-step explanation:
>_<
Top left 127
top middle 57
top right 118
bottom left 30
bottom middle 65
bottom right 36