The van can carry 6 students and bus can carry 21 students.
Step-by-step explanation:
Given,
High School A: 12 vans and 11 buses with 303 students
High School B: 6 vans and 7 buses with 183 students
To find the number of students that a van and a bus can carry.
Let us take,
The van can carry x students and the bus can carry y students.
According to the problem,
12x+11y = 303 ------- (1)
6x+7y = 183 ------- (2)
Multiplying 2 with (2) and subtract (1) and (2) we get,
(12x+11y) - 2(6x+7y) = 303-2(183)
or, 12x+11y-12x-14y = 303-366
or, -3y = -63
or, y = 21
From (2) we get,
6x+7(21) = 183
or, 6x = 183-147
or, 6x = 36
or, x = 6
Hence,
The van can carry 6 students and bus can carry 21 students.
Answer:
846.06 units
Step-by-step explanation:
The amount of profit, y, made by the company, is related to the selling price of each widget, x, by the given equation as follows :
...(1)
We need to find out the maximum amount of profit the company can make.
For maximum profit put dy/dx = 0
So,
Put x = 22.87 in equation (1). So,
So, the maximum profit is 846.06 units.
Step-by-step explanation:
yes hay has hay hay hay hay
Answer:
3.75
Step-by-step explanation:
Answer:
HA pretty sure
Step-by-step explanation:
It shows that the Hypotenuse and the 45 degree angle is the same on both triangles.