The distance travelled is 10 m
The velocity gained at the end of the time is 2 m/s
<h3>Motion</h3>
From the question, we are to determine distance travelled and the velocity gained
From one of the equations of motion for <u>linear motion</u>, we have that
S = ut + 1/2at²
Where S is the distance
u is the initial velocity
t is the time taken
and a is the acceleration
First, we will calculate the acceleration
Using the formula,
F = ma
Where F is the force
m is the mass
and a is the acceleration
∴ a = F/m
Where F is the force
and a is the acceleration
From the given information,
F = 50 N
m = 250 kg
Putting the parameters into the equation,
a = 50/250
a = 0.2 m/s²
Thus,
From the information,
u = 0 m/s (Since the object was initially at rest)
t = 10 s
S = 0(t) + 1/2(0.2)(10)²
S = 10 m
Hence, the distance travelled is 10 m
For the velocity
Using the formula,
v = u + at
Where v is the velocity
v = 0 + 0.2×10
v = 2 m/s
Hence, the velocity gained at the end of the time is 2 m/s
Learn more on Motion here: brainly.com/question/10962624
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Answer:
1. The corresponding sides of the two triangles must be proportional.
Step-by-step explanation:
Option 1, is the only statement that makes GHI = JKL true. If the triangles are congruent, it means that the sides have to be proportional.
When i calculated it , it says 993.813
Answer:
113.1 in.³
Step-by-step explanation:
V = (4/3)πr³
V = (4/3) × 3.14159 × (3 in.)³
V = 113.1 in.³
Answer:
96 ft^2.
Step-by-step explanation:
Area of shaded region = area of the original rectangle - area of the one removed
= 8 * 16 - 8*4
= 128 - 32
= 96
