All categories

3 years ago

A triangle on a coordinate plane is translated according to the rule T–8, 4(x, y). Which is another way to write this rule?

Mathematics

2 answers:

RSB [31]3 years ago

6 0

Answer:

(x, y) → (x - 8, y + 4)

Step-by-step explanation:

Anika [276]3 years ago

4 0

The answer is c (x,y)->(x-8,y+4)

You might be interested in

Twice the differencedifference of a number and 55 is equal to three times the sumsum of the number and 8.8.

bazaltina [42]

2*(n-55)=3*(n+8.8)
2n-110=3n+26.4
-136.4=n

8 0

4 years ago

Which graph shows the solution set of <img src="https://tex.z-dn.net/?f=%5Cfrac%7Bx-1%7D%7Bx-3%7D%20%5C%20%20%5Ctextless%20%5C%2

forsale [732]

Answer:

Step-by-step explanation:

f(x) = (x - 1)/(x - 3) < 0

The critical points are x = 1 and x = 3

When x < 1, f(x) > 0

When 1 < x < 3, f(x) < 0

When x > 3, f(x) > 0

Note when x = 3 f(x) has no value and when x = 1 f(x) = 0.

I can't see all the graphs very well but there should be a red line between 1 and 3 with a clear circle on x = 1 and x = 3.

Looks like its the last choice.

7 0

3 years ago

From a point Q, the length of the tangent to a circle is 24 cm and the distance of Q from the centre is 25 cm find the radius of

Umnica [9.8K]

$\large\bold{{Question :}}$

From a point Q, the length of the tangent to a circle is 24 cm and the distance of Q from the centre is 25 cm find the radius of the circle.

$\large\bold\red{\underline{Solution :-}}$

Here, O is the center of the circle.

⟼ Given :

OQ = 25 cm
PQ = 24 cm

⟼ To Find : We have to find the radius OP.

Since QP is tangent, OP perpendicular to QP.

(Since, Tangent is Perpendicular to Radius ⠀⠀⠀⠀⠀⠀⠀at the point of contact)

So, ∠OPQ=90°

⟼ By Applying Pythagoras Theorem :

OP² + RQ² = OQ²

OP² + (24)² = (25)²

OP² = 625 - 576

OP² = 49

OP = √49

OP = 7 cm

Hence, The Radius is 7 cm

⠀⠀

⠀

<h3>-MissAbhi</h3>

7 0

2 years ago

Read 2 more answers

Phil's shadow is half as long as Phil is tall. If he were 4 inches taller and his shadow were 3 inches

insens350 [35]

Answer:

Phil is 16 inches tall and his shadow is 8 inches tall

Step-by-step explanation:

this is an algebra word problem.

1. Find the unknown and label it x.

Let Phil's shadow be x inches.

2. find other unknown quantities and define them with

Phil's height= 2x (phil is shadow is half as long as Phil is tall)

3. FInd the equation

if he was 4 inches taller (2x+4)

and his shadow was three inches shorter (x-3)

his height ( 2x+4) times the shadow's height (x-3) would be 100 square inches.

(2x+4) ×(x-3)=100

(2x+4)(x-3)=100

this is a quadratic equation and there are a number of ways to solve these. the two main ways are

1. quadratic equation

2. expanding and factorising

3. graphing

we will use 2. expanding and factorising for this problem. We need to make the right hand side = 0 by first factorising then rearranging.

(2x*x)+(2x*-3)+(x*4) +(4*-3)=100

2x^2 -6x+4x-3x-12=100

2x^2 -2x=112

2x^2 -2x-112=0

once factorised take out the common factor of 2

2(x^2-x-56)=0

now factorise what's in the brackets ( two numbers multiply to make 56 but add to make -1.

2(x-8)(x+7)=0

x-8=0 => x=8

x+7=0 x=-7 not possible

the shadow is 8 inces long. Phil is 16 inches tall.

Hope this is of help :)

5 0

3 years ago

Simplify the expression below. 13y+x-7y

Zigmanuir [339]

13y+x-7y. The answer to this expression is 6y+x

8 0

3 years ago

Read 2 more answers