I think it is .8 i could be wrong i’m not sure
If y = cos(kt), then its first two derivatives are
y' = -k sin(kt)
y'' = -k² cos(kt)
Substituting y and y'' into 49y'' = -16y gives
-49k² cos(kt) = -15 cos(kt)
⇒ 49k² = 15
⇒ k² = 15/49
⇒ k = ±√15/7
Note that both values of k give the same solution y = cos(√15/7 t) since cosine is even.
Answer:
28
Step-by-step explanation:
If all the power of the variables are greater than or equal to zero, then the expression is a valid polynomial.
So,
1.



are polynomials.
2.

y
2 + s

are all polynomials.
3.
If the degree of the polynomial is 3, then it is a cubic polynomial. If the number of terms of a polynomial is 3, then it is a trinomial.
Hence,
is a cubic trinomial.
4.
The highest power is the degree.
Hence, degree of the polynomial is 2 + 4 = 6.