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Vaselesa [24]
3 years ago
10

What is the length to the nearest tenth, of the line segment joining the points (-4,2) and (146,52)

Mathematics
1 answer:
Vlad1618 [11]3 years ago
7 0
Finding the distance between (-4,2) and (146,52)

Use the distance formula<span> to determine the </span>distance<span> between the two </span>points<span>.
</span><span>Distance= </span>√<span>(<span>x2</span>−<span>x1</span><span>)^2</span>+(<span>y2</span>−<span>y1</span><span>)^2

</span></span>Substitute the actual values of the points<span> into the </span>distance formula<span>.
</span>√<span>((146)−(−4)<span>)^2</span>+((52)−(2)<span>)^2

</span></span>Simplify the expression<span>.
</span>√19400<span>

</span>Rewrite 19400<span> as </span><span><span><span>10^2</span>⋅194</span>.
</span>√10^<span>2⋅194
</span>
Pull terms<span> out from under the </span>radical<span>.
</span>10√<span>194

</span>The approximate<span> value for the </span>distance<span> between the two </span>points<span> is </span><span>139.28389.
</span>
10√<span>194≈139.28389</span>
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worty [1.4K]

J (-4, 1), K (-4, -2), L (-3, -1)

(a) To rotate a point 90° counterclockwise about the origin, multiply the y-coordinate by -1 and then interchange the z- and y- coordinates.

(x, y)'' = (-y, x)

Substitute all of J (-4, 1), K (-4, -2), L (-3, -1) for (x, y)

Solution:

J'' = J (-4, 1) × (x, -1) = (-4, -1)

K'' = K (-4, -2) × (x, -1) = (-4, 2)

L'' = L (-3, -1) × (x, -1) = (-3, 1)

J'' (-1, -4), K'' (2, -4), L'' (1, -3)

Image ▲J"K"L": Look at the first attached picture.

(b) To reflect a point in the y-axis, we multiply its x-coordinate by -1.

Substitute all of J (-4, 1), K (-4, -2), L (-3, -1) for (x, y)

Multiplying by -1:

J'' = J (-4, 1) × (-1, y) = (4, 1)

K'' = K (-4, -2) × (-1, y) = (4, -2)

L'' = L (-3, -1) × (-1, y) = (3, -1)

J'' (4, 1), K'' (4, -2), L'' (3, -1)

Image ▲J"K"L": Look at the second attached picture.



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