Question

Find the area of the triangle with the given measurements.Round the solution to the nearest hundredth if necessary.A=50 degrees,b=31,c=18ft

Answer 1

Answer:

$\large\boxed{A\approx213.71\ ft^2}$

Step-by-step explanation:

Use the formula:

$A=\dfrac{1}{2}bc\sin A$

We have:

$b=31\ ft,\ c=18\ ft,\ m\angle A=50^o\to\sin50^o\approx0.766$

Substitute:

$A=\dfrac{1}{2}(31)(18)(0.766)\approx213.71\ ft^2$