Answer:
Step-by-step explanation:
Juan has 20 books to sell. He sells the books for $15 each.
The range of the function is the set of all possible values of the dependent variable. The dependent variable here is the amount of money that is made and this amount depends on
the number of books, x sold
The amount of money Juan makes from selling books is represented by a fucntion. f(x)=15x
The maximum amount that can be made from 20 books at a rate of $15 each would be 20×15 = $300
The minimum amount that fan be made is $0 and this is when no book is sold. Let y = f(x). So the range is
0 lesser than or equal to y lesser than or equal to 300
Answer:
c = 2 * 3.14 * r and c = 3.14 * d
Step-by-step explanation:
The formulas for the circumference of a circle are
c = 2πr and c = πd
where r is the radius and d is the diameter
using π = 3.14
the formulas become
c = 2 * 3.14 * r and c = 3.14 * d
Unfortunately you haven't shared the possible answer choices from the "drop-down menu." Please do that.
Please figure out the area of the actual (full-sized) apartment.
Think of the intermediate steps you'd have to follow to construct a scale model to the given scale.
Answer: In right triangle XZW, the height WY is the geometric mean of segments ZY and XY.
Hence,
4^2=3 x a,
a=16/3 un.
Answer:
525
Step-by-step explanation:
This is a question involving combinatorics
The number of ways of choosing a subset k from a set of n elements is given by 
which evaluates to 
n! is the product n × (n-1) × (n-2) x....x 3 x 2 x 1
For example,
4! = 4 x 3 x 2 x 1 = 24
3! = 3 x 2 x 1 = 6
Since we have to choose 4 boys from a class of 6 boys, the total number of ways this can be done is
Note that 6! = 6 x 5 x 4 x 3 x 2 x 1 and 4 x 3 x 2 x 1 is nothing but 4!
So the numerator can be re-written as 6 x 5 x (4!)
We can rewrite the expression 
Cancelling 4! from both numerator and denominator gives us the result
as (6 × 5)/2! = 20/2 = 15 different ways of choosing 4 boys from a class of 6 boys
For the girls, the number of ways of choosing 3 girls from a class of 7 girls is given by
This works out to (7 x 6 x 5 )/(3 x 2 x 1) (using the same logic as for the boys computation)
= 210/6 = 35
So total number of committees of 4 boys and 3 girls that can be formed from a class of 6 boys and 7 girls = 15 x 35 = 525
