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3 years ago

What is the x-value in the solution to this system of linear equations?

1 answer:

6 0

First put the first equation in Y= which is:
Y=2x-11
So we can substitute this in for Y.
X+3(2x-11)=-5
Now solve for X
X+6x-33=-5
7X=28
X=4

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3 years ago

A water storage tank is in the shape of a hemisphere (half a sphere). If the radius is 20 ft, approximate the volume of the t

otez555 [7]

Answer:

The approximate volume of the tank is $V=16,747\ ft^{3}$

Step-by-step explanation:

we know that

The volume of a hemisphere (water storage tank) is equal to

$V=\frac{4}{6}\pi r^{3}$

we have

$r=20\ ft$

assume

$\pi =3.14$

substitute

$V=\frac{4}{6}(3.14)(20)^{3}$

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3 years ago

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3 years ago

One gallon of paint covers 400 square feet of surface area. A typical spherical water tower holds 66,840.28 cubic feet of water.

enot [183]

Answer: There will enough to paint the outside of a typical spherical water tower.

Step-by-step explanation:

1. Solve for the radius r from the formula for calculate the volume of a sphere. as following:

$V=\frac{4}{3}r^{3}\pi\\\frac{3V}{4\pi}=r^{3}\\r=\sqrt[3]{\frac{3V}{4\pi}}$

2. Substitute values:

$r=\sqrt[3]{\frac{3(66,840.28ft^{3})}{4\pi}}=25.17ft$

3. Substitute the value of the radius into the equation fo calculate the surface area of a sphere, then you obtain that the surface area of a typical spherical water tower is:

$SA=4r^{2}\pi\\SA=4(25.17ft)^{2} \pi\\SA=7,964.95ft^{2}$

3. If a city has 25 gallons of paint available and one gallon of paint covers 400 square feet of surface area, you must multiply 25 by 400 square feet to know if there will be enough to paint the outside of a typical spherical water tower.

$25*400ft^{2}=10,000ft^{2}$

As you can see, there will enough to paint the outside of a typical spherical water tower.

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3 years ago