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Whitepunk [10]
2 years ago
10

Water vapor forming ice crystals on the window on a cold winter day is and example of

Physics
2 answers:
user100 [1]2 years ago
8 0
Answer: Deposition.
photoshop1234 [79]2 years ago
5 0

Answer:

Deposition

Explanation:

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If light travels from oil (slower medium) to water (faster medium) at an angle, what happens to the direction of the light ray i
iVinArrow [24]
If light travels from oil to water at an angle, what happens to the direction of the light ray in water with respect to the normal, is it moves away from the normal.
7 0
3 years ago
Example No. 10
Alexxx [7]

The force constant of the spring is determined as 14,222.2 N/m.

<h3>Force constant of the spring</h3>

Apply the principle of conservation of energy,

K.E = U

where;

  • K.E kinetic energy of the elevator
  • U is elastic potential energy of the spring

¹/₂mv² = ¹/₂kx²

mv² = kx²

k = mv²/x²

Where;

  • m is mass of the elevator
  • v is speed
  • x is compression of the spring

k = (2000 x 8²)/(3²)

k = 14,222.2 N/m

Thus, the force constant of the spring is determined as 14,222.2 N/m.

Learn more about force constant here: brainly.com/question/1968517

#SPJ1

5 0
1 year ago
Where are streams located?
Zolol [24]

Answer:

Hello there!

Explanation:

A river is a natural flowing watercourse, usually freshwater, flowing towards an ocean, sea, lake or another river. In some cases a river flows into the ground and becomes dry at the end of its course without reaching another body of water. Small rivers can be referred to using names such as stream, creek, brook, rivulet, and rill.

hope this helps!

6 0
2 years ago
You are given a sample of metal and asked to determine its specific heat. You weight the sample and find that its weight is 28.4
lidiya [134]

Answer:

The samples specific heat is 14.8 J/kg.K

Explanation:

Given that,

Weight = 28.4 N

Suppose, heat energy E=1.25\times10^{4}\ J

Temperature = 18°C

We need to calculate the samples specific heat

Using formula of specific heat

Q=mc\Delta T

c=\dfrac{Q}{m\Delta T}

Where, m = mass

c = specific heat

\Delta T = temperature

Q = heat

Put the value into the formula

c=\dfrac{1.25\times10^{4}}{\dfrac{28.4}{9.8}\times(18+273)}

c=14.8\ J/kg. K

Hence, The samples specific heat is 14.8 J/kg.K

8 0
3 years ago
An object with a mass of 2.0 kg accelerates 2.0 m/s2 when an unknown force is applied to it. What is the amount of the force?
MAXImum [283]

force is mass * acceleration  

so 2kg * 2m/s^2 = 4 N

5 0
3 years ago
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