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4 years ago

5

Please anyone please help me with this question

1 answer:

marin [14]4 years ago

8 0

Well, It's going to be 8/12 and then reduced it will be 4/6 or 0.667

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Find the permeter of a quadrilateral with vertices at C (2,4), D(1,1), E(5,0), and F(3,4). Round your answer to the nearest hund

denpristay [2]

Answer:

12.76

Step-by-step explanation:

This is much easier to solve if you draw it out on a graph. The perimeter is the sum of all the sides. I used the Pythagorean theorem to find the hypotenuse.

${a}^{2} + {b}^{2} = {c}^{2} \\ c = \sqrt{ {a}^{2} + {b}^{2} }$

$dc = \sqrt{ {3}^{2} + {1}^{2} } = \sqrt{10} \\ cf = 1 \\ fe = \sqrt{ {4}^{2} + {2}^{2} } = \sqrt{20} \\ de = \sqrt{ {1}^{2} + {4}^{2} } = \sqrt{17} \\ \sqrt{10} + 1 + \sqrt{20} + \sqrt{17} = 12.76$

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jonny [76]

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LenaWriter [7]

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Step-by-step explanation:

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