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gogolik [260]
3 years ago
11

A person invests 4500 dollars in a bank. The bank pays 6.75% interest compounded semi-annually. To the nearest tenth of a year,

how long must the person leave the money in the bank until it reaches 6300 dollars?
Mathematics
1 answer:
sergiy2304 [10]3 years ago
3 0

Answer:

Step-by-step explanation:

We would apply the formula for determining compound interest which is expressed as

A = P(1+r/n)^nt

Where

A = total amount in the account at the end of t years

r represents the interest rate.

n represents the periodic interval at which it was compounded.

P represents the principal or initial amount deposited

From the information given,

P = 4500

A = 6300

r = 6.75% = 6.75/100 = 0.0675

n = 2 because it was compounded 2 times in a year.

Therefore,.

6300 = 4500(1 + 0.0675/2)^2t

6300/4500 = (1 + 0.03375)^2t

1.4 = 1.03375^2t

Taking log of both sides of the equation, it becomes

Log 1.4 = 2t log 1.03375

0.1461 = 2t × 0.0144 = 0.0288t

t = 0.1461/0.0288

t = 5.1 years.

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