The area of square is
square units
<h3><u>Solution:</u></h3>
Given that square has side length (x+5) units
To find: area of square
<em><u>The area of square is given as:</u></em>
![\text {Area of square }=\mathrm{a}^{2}](https://tex.z-dn.net/?f=%5Ctext%20%7BArea%20of%20square%20%7D%3D%5Cmathrm%7Ba%7D%5E%7B2%7D)
Where "a" is the length of side
From question, length of each side "a" = x + 5 units
Substituting the value in above formula,
![\text {Area of square }=(x+5)^{2}](https://tex.z-dn.net/?f=%5Ctext%20%7BArea%20of%20square%20%7D%3D%28x%2B5%29%5E%7B2%7D)
![{\text {Expanding }(x+5)^{2} \text { using the algebraic identity: }} \\\\ {(a+b)^{2}=a^{2}+2 a b+b^{2}}\end{array}](https://tex.z-dn.net/?f=%7B%5Ctext%20%7BExpanding%20%7D%28x%2B5%29%5E%7B2%7D%20%5Ctext%20%7B%20using%20the%20algebraic%20identity%3A%20%7D%7D%20%5C%5C%5C%5C%20%7B%28a%2Bb%29%5E%7B2%7D%3Da%5E%7B2%7D%2B2%20a%20b%2Bb%5E%7B2%7D%7D%5Cend%7Barray%7D)
![\begin{array}{l}{\text {Area of square }=x^{2}+2(x)(5)+5^{2}} \\\\ {\text {Area of square }=x^{2}+10 x+25}\end{array}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Bl%7D%7B%5Ctext%20%7BArea%20of%20square%20%7D%3Dx%5E%7B2%7D%2B2%28x%29%285%29%2B5%5E%7B2%7D%7D%20%5C%5C%5C%5C%20%7B%5Ctext%20%7BArea%20of%20square%20%7D%3Dx%5E%7B2%7D%2B10%20x%2B25%7D%5Cend%7Barray%7D)
Thus the area of square is
square units
D. 35, since that would be the longest amount. of time walking away from her house, she should be the farthest amount of feet away from her house
Answer:
ok what teacher gave you this
Step-by-step explanation: