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3 years ago

Sorry ignore this question.

Mathematics

2 answers:

Anna11 [10]3 years ago

7 0

Okay

(Thanks for the points)

forsale [732]3 years ago

7 0

heheheh im totally not writing just for the points *says sarcatically*

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At a discount electronic store, Kristoff offered a salesperson $600 for a television and table. The offer includes the 8% sales

Alex73 [517]

B. 8% of 556 = 44.8
44.8 + 556 = 600 rounded.

8 0

2 years ago

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HELP PLS I WILL MARK BRAINLIEST, DUE TODAYY 100 POINTS!!!!!!!!!

Flauer [41]

Answer:

Y1 intercept = 2

(0,2) (3,-7)

m= (-7 - 2) / (3-0) =-9/3 = - 3

Then y = - 3x + 2

Y2 intercept = - 8

(0,-8) (3,-7)

m = (-7 - - 8) / (3-0) = 1/3

Then y= (1/3)x-8

5 0

2 years ago

Find the product of<br>the sum of<br>3/5 and 1%<br>and

dybincka [34]

Answer:

3/500

Step-by-step explanation:

3/5 x 1%

=> 3/5 x 1/100

=> 3/500

Hope it helps you

8 0

2 years ago

Match each set of vertices with the type of triangle they form.

Andrew [12]

Answer: The calculations are done below.

Step-by-step explanation:

(i) Let the vertices be A(2,0), B(3,2) and C(5,1). Then,

$AB=\sqrt{(2-3)^2+(0-2)^2}=\sqrt{5},\\\\BC=\sqrt{(3-5)^2+(2-1)^2}=\sqrt{5},\\\\CA=\sqrt{(5-2)^2+(1-0)^2}=\sqrt{10}.$

Since, AB = BC and AB² + BC² = CA², so triangle ABC here will be an isosceles right-angled triangle.

(ii) Let the vertices be A(4,2), B(6,2) and C(5,3.73). Then,

$AB=\sqrt{(4-6)^2+(2-2)^2}=\sqrt{4}=2,\\\\BC=\sqrt{(6-5)^2+(2-3.73)^2}=\sqrt{14.3729},\\\\CA=\sqrt{(5-4)^2+(3.73-2)^2}=\sqrt{14.3729}.$

Since, BC = CA, so the triangle ABC will be an isosceles triangle.

(iii) Let the vertices be A(-5,2), B(-4,4) and C(-2,2). Then,

$AB=\sqrt{(-5+4)^2+(2-4)^2}=\sqrt{5},\\\\BC=\sqrt{(-4+2)^2+(4-2)^2}=\sqrt{8},\\\\CA=\sqrt{(-2+5)^2+(2-2)^2}=\sqrt{9}.$

Since, AB ≠ BC ≠ CA, so this will be an acute scalene triangle, because all the angles are acute.

(iv) Let the vertices be A(-3,1), B(-3,4) and C(-1,1). Then,

$AB=\sqrt{(-3+3)^2+(1-4)^2}=\sqrt{9}=3,\\\\BC=\sqrt{(-3+1)^2+(4-1)^2}=\sqrt{13},\\\\CA=\sqrt{(-1+3)^2+(1-1)^2}=\sqrt 4.$

Since AB² + CA² = BC², so this will be a right angled triangle.

(v) Let the vertices be A(-4,2), B(-2,4) and C(-1,4). Then,

$AB=\sqrt{(-4+2)^2+(2-4)^2}=\sqrt{8},\\\\BC=\sqrt{(-2+1)^2+(4-4)^2}=\sqrt{1}=1,\\\\CA=\sqrt{(-1+4)^2+(4-2)^2}=\sqrt{13}.$

Since AB ≠ BC ≠ CA, and so this will be an obtuse scalene triangle, because one angle that is opposite to CA will be obtuse.

Thus, the match is done.

4 0

3 years ago

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What is the difference between the range of the electoral votes per state and the modal number of electoral votes in the followi

-Dominant- [34]

The difference is 45.

The modal number of the electoral votes is 5 because it appears the most.

The range of the electoral votes is 55 - 5 = 50 (Highest minus the lowest).

The difference between the two is found by subtracting them.
50 - 5 = 45

6 0

2 years ago

Read 2 more answers