On a coordinate plane, the vertices of a

Black_prince [1.1K]

To solve, you start with distributive property and multiply 7 by n and 3 for
7n-21<-63 the you get the 7n alone by adding 21 to -63 and the 21 for 7n<-42. now you divide 7 by itself and 42 for n<-6

7 0

3 years ago

Read 2 more answers

find an equation that is used in real life to solve problems. tell what your equation does. identify the variables and what the

andrezito [222]

If we in the following equation y=x+7 assigns a value to x, the equation will give us a value for y. ... We could instead have assigned a value for y and solved the equation to find ... the independent variable, and the other variable is the dependent variable, ... A function is an equation that has only one answer for y for every x

7 0

4 years ago

A computer chess game and a human chess champion are evenly matched. They play ten games. Find probabilities for the following e

AleksAgata [21]

Answer:

(a) The probability that each of them win five games is 0.2461.

(b) The probability that the computer wins seven games is 0.1172.

(c) The probability that the human wins at least 7 games is 0.1711.

Step-by-step explanation:

Let the random variable X = the human wins a chess game.

The probability that the human wins a game is, P (X) = p = 0.50.

The number of games played by the computer and the human is, n = 10.

The random variable $X\sim Bin(n = 10,p=0.50)$

The probability distribution of the Binomial random variable X is:

$P (X=x)={n\choose x}p^{x}(1-p)^{n-x}={10\choose x}(0.50)^{x}(1-0.50)^{10-x}$

(a)

If both the computer and the human wins five games each then the probability of the human winning 5 games is:

$P (X=5)={10\choose 5}(0.50)^{5}(1-0.50)^{10-5}\\=252\times 0.03125\times0.03125\\=0.246094\\\approx 0.2461$

Thus, the probability that each of them win five games is 0.2461.

(b)

If the computer wins 7 games then the number of games won by the human is, 10 - 7 = 3.

P (Computer winning 7 games) = P (Human winning 3 games)

The probability that the human wins 3 games is:

$P (X=3)={10\choose 3}(0.50)^{3}(1-0.50)^{10-3}\\=120\times 0.125\times0.0078125\\=0.1171875\\\approx 0.1172$

Thus, the probability that the computer wins seven games is 0.1172.

(c)

Compute the probability that the human wins at least 7 games as follows:

$P(X\geq 7)=P(X=7)+P(X=8)+P(X=9)+P(X=10)\\={10\choose 7}(0.50)^{7}(1-0.50)^{10-7}+{10\choose 8}(0.50)^{8}(1-0.50)^{10-8}\\+{10\choose 9}(0.50)^{9}(1-0.50)^{10-9}+{10\choose 10}(0.50)^{10}(1-0.50)^{10-10}\\=0.1172+0.044+0.009+0.0009\\=0.1711$

Thus, the probability that the human wins at least 7 games is 0.1711.

5 0

4 years ago

Find the solution sets for 4

Ket [755]

Answer:

??????????????????? 3+1

Step-by-step explanation:

5 0

3 years ago

The final velocity of an object moving in one dimension is given by the formula v = u + at, where u is the

kodGreya [7K]

The answer is the last one

6 0

4 years ago