Cat is out on the first day:
<span>240: 5 = 48 t </span>
<span>What remains after you take it out on day 48 t </span>
<span>240-48 = 192 t </span>
<span>Cat is out in the next </span>
<span>192 6 = 32t </span>
<span>What remains after you take it out 32 t of the day? </span>
<span>192-32 = </span>160t<span>
</span>
Answer: No solution
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Answer:
C
Step-by-step explanation:
Answer:
q=-5
Step-by-step explanation:
6+q=1
Isolate the variable by subtracting 6 from both sides of the equation
q=1-6
q=-5
x=6 , y = 4
Step-by-step explanation:
( x-2,6)=(4,Y+2)
this means; (x-2) &( 4) stands for" x "axis.
and( 6 )& (y+2) stands for y axis.
So, we can say( x-2)=X1 & (4)=X2 , (6)=Y1 & (y+2)=Y2
then; to Solve The Equation we use The Formula: X1=X2 for "X" And Y1=Y2 for "Y".
Solution: for "X" ; X1=X2
x-2= 4
x=4+2
x=<u>6</u>
For "Y" ; Y1=Y2
6 = y+2
y=6-2
y=<u>4</u>
finally check ; ( (x-2),6) = (4,(y+2) )
(6-2),6 = (4,(4+2) )
( (4),6) = (4,(6) )
(4,6) = (4,6)
so, X1 =X2 ; 4 = 4
Y1 = Y2 ; 6 = 6
