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mr Goodwill [35]
3 years ago
6

Combine like terms. y+6 - 2 – 4y^3– 5y + 2y^3 – 2y^3

Mathematics
1 answer:
Step2247 [10]3 years ago
6 0

Answer: −4y + 4 − 4y^{3}

Step-by-step explanation:

Hey there! I will give the following steps, if you have any questions feel free to ask me in the comments below.

<u>Step 1:</u><u> </u><u><em>Collect like terms.</em></u>

(y − 5y) + (6 − 2) + (−4y^{3} + 2y^{3} − 2y^{3})

<u>Step 2: </u><u><em>Simplify.</em></u>

−4y + 4 − 4y^{3}

~I hope I helped you! :)~

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Will give brainliest!!! Determine the answer to (−5) + 4 and explain.
algol13

Answer:

The answer is -1 because adding onto a negitive number makes the number go towards 0

Step-by-step explanation:

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4 years ago
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Evaluate the expression a + b for a = 25 and b = 2.
jenyasd209 [6]
25 plus 2 equals 27 ahahhaaishah
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3 years ago
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Match each statement in the proof with the correct reason.
Masteriza [31]

Answer:

See explanation

Step-by-step explanation:

<u>Definition of parallelogram:</u> Parallelogram is a quadrilateral with two pairs of parallel sides.    

<u>Definition of transversal (diagonal):</u> A line that cuts across two or more (usually parallel) lines.

<u>Definition of the same side interior angles:</u> These angles are located exactly as their name describes. They are "interior" (between the parallel lines), and they are on the same side of the transversal (diagonal).

<u>The same-side interior angles theorem</u> states that when two lines that are parallel are intersected by a transversal line, the same-side interior angles that are formed are supplementary

       Statement                          Reason

1. ABCD is a parallelogram  -  Given

2. \overline{AB}\parallel \overline {CD}                           -  Definition of parallelogram

3. \overline{AD} is a diagonal of \overline{AB} and \overline{CD} - Definition of diagonal

4.  \angle A and \angle D are the same side interior angles - Definition of same-side interior angles

5.  \angle A is supplementary to  \angle D - Same-Side Interior Angles Theorem

5 0
3 years ago
Weekly demand for a particular item averages 30 units, with a standard deviation of 4. This item is managed with a fixed-order-i
aivan3 [116]

Answer:

(B)93

Explanation:

Since we are using a fixed-order-interval model,

The Amount to Order=Expected Demand During protection Interval+Safety Stock-Amount at Hand

=d(OI+LT)+z\sigma_{d}\sqrt{OI+LT}-A

Where:  

d=weekly demand

OI=Order Interval

LT=Lead Time

z=Standard Deviation of Desired Service Level

\sigma_{d}=Standard Deviation of weekly Demand

A= Amount at Hand

=d(OI+LT)+z\sigma_{d}\sqrt{OI+LT}-A

[30(3 + 1)] + [1.964*4*\sqrt{3 + 1} - 43

= 120 + 15.712 - 43 = 92.7

4 0
3 years ago
I need help!!!
Nataly_w [17]

Answer:

y = 3

Step-by-step explanation:

8(y + 2) = 40 \\ y + 2 =  \frac{40}{8}  \\ y + 2 = 5 \\ y = 5 - 2 \\ y = 3

6 0
3 years ago
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