Let’s start by considering any 2 points falling on the line, the intercepts are the ones which come to my mind. Thus, the line 2x+3 will originally intersect the x- axis at (−32,0) and the y- axis at (0,3).
So, the basic insight is that on rotating the origin, the axes rotate. But the intercepts (their lengths) don’t change. The axis that is being intercepted will change, not the distance of intercepting points from the origin until our line is itself rotated. (Keep scribbling)
For the first case, we rotate the axes clockwise by a right angle. Now notice that the negative x-axis replaces the positive y-axis. So, our line now intercepts the negative x- axis at a distance 3 from the origin. Similarly, the negative y- axis replaces the negative x- axis. So, our line intersects the negative y- axis at distance 1.5 .
Therefore, the new intercepts are X(−3,0) and Y(0,−1.5). We can hence produce the new equation for our line in the slope- intercept form as
y=−x2−1.5 .
Similarly, you can imagine the other cases as axes rotation/replacement.
For 180∘, the equation would be y=2x−3 .
For 270∘, the equation would be y=−x2+1.5 .
40/5 is 8, so when t=1, r=8.
8 • 11 is 88, so when t=11, r=88.
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Answer:
L'(4, -3)
Step-by-step explanation:
The reflection over the horizontal line y=-1 effects the transformation ...
(x, y) ⇒ (x, -2-y)
So, the coordinates of L are transformed to ..
L(4, 1) ⇒ L'(4, -2-1) = L'(4, -3)
-73/100 is one. Hope that helped! If you need another example PM me and i can list some more :)
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