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dolphi86 [110]
3 years ago
9

Help!!

Mathematics
1 answer:
kap26 [50]3 years ago
5 0
The algebraic expression would be:
-11+x
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Mr. and Mrs. Nelson are going to build a new home. They need to have working drawings of their house plans created by a design f
matrenka [14]

Answer:

Options 2), 4), and 5) are correct

Step-by-step explanation:

<u>Rock the House Digital Designs</u>

  • Cost = $(500 + 50h)

<u>Elegant Home Architects</u>

  • Cost = $(75h)

===========================

<u>Answer options:</u>

1)The expression 50h represents the total charge for Rock the House Digital Designs.

  • Incorrect. Additional $500 charged.

2)The expression 75h represents the total charge for Elegance Home Architects.

  • Correct

3)The expression 500 + 75h + 50h represents the total amount the Nelsons will spend working drawings of their new house plans.

  • Incorrect. They will choose one of the options.

4)If the Nelsons hire the design firm for 15 hours, then Elegance Home Architects will be cheaper.

  • Correct. It will cost 15*75 = $1125. Alternative costs 500 + 50*15 = $1250

5)If the Nelsons hire the design firm for 25 hours, then Rock the House Digital Designs will be cheaper.

  • Correct. It will cost 500+25*50 = $1750. Alternative cost is 25*75 = $1875
8 0
4 years ago
Find the value of x then classify the triangle by its angles
Neporo4naja [7]

Answer:

Step-by-step explanation:

3x + x + 60 = 180.

first, we add the x's together.

4x + 60 = 180

then we see if they all have a common multiple. in this case, they do. they are all divisible by 4, so we can use that.

x + 15 = 45

then, just subtract 15 from both sides, that way we get the variable by itself.

x = 30

also, it is a right triangle. the top angle (3x) multiplied by 3 is 90. any triangle that has a 90 degree angle is automatically a right triangle.

6 0
3 years ago
Read 2 more answers
Given $a \equiv 1 \pmod{7}$, $b \equiv 2 \pmod{7}$, and $c \equiv 6 \pmod{7}$, what is the remainder when $a^{81} b^{91} c^{27}$
Blizzard [7]
\begin{cases}a\equiv1\pmod7\\b\equiv2\pmod7\\c\equiv6\pmod7\end{cases}

a^{81}\equiv1^{81}\equiv1\pmod7

b^{91}\equiv2^{91}\pmod7

2^{91}\equiv(2^3)^{30}\times2^1\equiv8^{30}\times2\pmod7
8\equiv1\pmod7
2\equiv2\pmod7
\implies2^{91}\equiv1^{30}\times2\equiv2\pmod7

c^{27}\equiv6^{27}\pmod7

6^{27}\equiv(-1)^{27}\equiv-1\equiv6\pmod7

\implies a^{81}b^{91}c^{27}\equiv1\times2\times6\equiv12\equiv5\pmod7
6 0
3 years ago
Hmmmmmmmmmmmmmmmmmmmmmmmmmmm
belka [17]

\dfrac{6}{7}cd=\dfrac{6}{7}\cdot c\cdot d\\\\Factors:\ \dfrac{6}{7},\ c,\ d\\\\6x^2+7xy+3+9\\\\Constans\ (without\ x\ and\ y):\ 3,\ 9\\\\2x-4y+8=(2x)+(-4y)+(8)\\\\Terms:\ 2x,\ -4y,\ 8

4 0
3 years ago
What pattern of 7, 15,27​
GarryVolchara [31]
Ok well what I did but I’m not sure if it answers your question but I did 27-15=12-7=5 and that what I got maybe it’s 5 it’s just an assumption
7 0
3 years ago
Read 2 more answers
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