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Aleks04 [339]
3 years ago
15

Kevin opened a savings account with Texas National Bank. His account has an APR of 1.95% compounded quarterly. If Kevin opens hi

s account with $2100, how long will it take for the account to earn $10500?
Mathematics
1 answer:
ELEN [110]3 years ago
7 0

Answer:

82 years and 3 quarters

Step-by-step explanation:

A = P (1 + r / n)ⁿˣ

P = Principal amount

r = Annual interest rate

n = Number of compounds per year

x = time in years

A = Amount after time 'x'

10500 = 2100 (1 + 0.0195 / 4)⁴ˣ

Divide the whole equation by 2100

10500 / 2100 = ({2100 (1 + 0.004875)} / 2100 )⁴ˣ

5 = (1.004875)⁴ˣ

Taking Natural logarithm (㏑) on both sides

㏑ 5 = ㏑ (1.004875)⁴ˣ

㏑ 5 = 4x ㏑ (1.004875)

1.6094 = 4x (0.004863)

1.6094 = 0.01945x

x = 82.75

So, If compounded quarterly at an APR of 1.95% the amount deposited in savings account of $2100 will accumulate to $10500 in 82 years and 3 quarters.

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Point G is on line segment FH. Given FG=5x+2,GH=3x-1, and FG=9, determine the numerical length of FG
stealth61 [152]

Given:

FG=5x+2

GH=3x-1

FG=9

Let us draw the line segment as follows,

Equating the length of FG, we get,

\begin{gathered} 5x+2=9 \\ 5x=9-2 \\ 5x=7 \\ x=\frac{7}{5} \end{gathered}

Substitute the value of x in the given value of GH,

\begin{gathered} GH=3x-1 \\ =3(\frac{7}{5})-1 \\ =\frac{21}{5}-1 \\ =\frac{16}{5} \\ =3.2 \end{gathered}

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\begin{gathered} FH=FG+GH \\ =9+3.2 \\ =12.2 \end{gathered}

Hence, the lengths are,

\begin{gathered} FG=9 \\ GH=3.2 \\ FH=12.2 \end{gathered}

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