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Rzqust [24]
3 years ago
7

Tell whether the relation is a function (3,-2)(0,1)(1,0)(-2,-1)(2,-1)

Mathematics
2 answers:
GREYUIT [131]3 years ago
8 0

Have a look at the first elements of each point:  {3, 0, 1, -2, 2}.  Since these are all different, no one x value has more than one y-value associated with it, and thus (3,-2)(0,1)(1,0)(-2,-1)(2,-1) is a function.

telo118 [61]3 years ago
3 0

<u>answer:</u> it's a function

<u>explanation:</u> the reason why it's a function is when the x's are NOT repeating itself. when it's not a function, it the x's ARE repeating itself.

hope this helps! ❤ from peachimin

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Answer:

The completed proof is presented as follows;

The two column proof is presented as follows;

Statements    {}                                               Reason

1. \overline {HI} ║ \overline {KL}, J is the midpoint of \overline {HL} {}         1. Given

2. ∠IHJ ≅ ∠JLK{}                                            2. Alternate angles are congruent

3. ∠IJH ≅ ∠KJL   {}                                         3. Vertically opposite angles

4.  \overline {HJ} ≅ \overline {JL}   {}                                              4. Definition of midpoint

5. ΔHIJ ≅ ΔLKJ  {}                                         5. By ASA rule of congruency

Step-by-step explanation:

Alternate angles formed by the crossing of the two parallel lines \overline {HI} and \overline {KL}, by the transversal \overline {HL} are equal

Vertically opposite angles formed by the crossing of two straight lines \overline {IK} and \overline {HL} are always equal

A midpoint divides a line into two equal halves

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