Simplify (5 - p2 - 4q) - ( -2 + q - 3p2) plss hurry!!!!
2 answers:
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Answer: (a) (b)
Step-by-step explanation:
(a) P( Bill hitting the target) = 0.7 P( Bill not hitting the target) = 0.3
P( George hitting the target) = 0.4 P(George not hitting the target) = 0.6
Now the chances that exactly one shot hit the target is = 0.7 x 0.6 + 0.4 x 0.3
= 0.54
Chances that George hit the target is = 0.4 x 0.3 = 0.12
So given that exactly one shot hit the target, probability that it was George's shot = =
.
(b) The numerator in the second part would be the same as of (a) part which is 0.12.
The change in the denominator will be that now we know that the target is hit so now in denominator we include the chance of both hitting the target at same time that is 0.4 x 0.7 and the rest of the equation is same as above i.e.
Given that the target is hit,probability that George hit it = = =
9514 1404 393
Answer:
Emma's flight is farther from the airport
Step-by-step explanation:
Even without doing any detailed calculation, you can see on a graph that the larger turn Alice's flight makes keeps it closer to the airport.
Emma's flight is farther from the airport.
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The distance can be calculated using the Law of Cosines. The angle of interest is the supplement of the turn angle. Since the leg distances are the same in each case, the only variable affecting the distance from the airport is the angle measure. Again, the larger the turn, the shorter the distance from the airport. If T is the turn angle, the distance is ...
d² = 100² +50² -2·100·50·cos(180° -T)
d² = 12500 +10000·cos(T) . . . . . . . using cos(180°-T) = -cos(T)
d = 100√(1.25+cos(T))
For Alice's 70° turn, the distance is ...
d = 100√(1.25+0.342) ≈ 126.18 mi
For Emma's 50° turn, the distance is ...
d = 100√(1.25 +0.643) ≈ 137.58 mi
Emma's flight is farther from the airport.
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The law of cosines formula is ...
c² = a² +b² -2ab·cos(C)
where triangle sides are lengths a, b, c and angle C is opposite side c.
