All categories

3 years ago

Simplify (5 - p2 - 4q) - ( -2 + q - 3p2) plss hurry!!!!

Mathematics

2 answers:

jonny [76]3 years ago

5 0

Answer:

2p^2−5q+7

Step-by-step explanation:

Let's simplify step-by-step.

5−p2−4q−(−2+q−3p2)

Distribute the Negative Sign:

=5−p2−4q+−1(−2+q−3p2)

=5+−p2+−4q+(−1)(−2)+−1q+−1(−3p2)

=5+−p2+−4q+2+−q+3p2

Combine Like Terms:

=5+−p2+−4q+2+−q+3p2

=(−p2+3p2)+(−4q+−q)+(5+2)

=2p2+−5q+7

Answer:

=2p^2−5q+7

Grace [21]3 years ago

5 0

Answer:

2p²−5q+7

Explanation:

5−p²−4q−(−2+q−3p²)

Distribute the Negative Sign:

=5−p²−4q+−1(−2+q−3p²)

=5+−p²+−4q+(−1)(−2)+−1q+−1(−3p²)

=5+−p2+−4q+2+−q+3p2

Combine Like Terms:

=5+−p²+−4q+2+−q+3p²

=(−p²+3p²)+(−4q+−q)+(5+2)

=2p²+−5q+7

You might be interested in

6) What is 13% of 33.39?

icang [17]

Answer:

1. We assume, that the number 33.39 is 100% - because it's the output value of the task.

2. We assume, that x is the value we are looking for.

3. If 33.39 is 100%, so we can write it down as 33.39=100%.

4. We know, that x is 13% of the output value, so we can write it down as x=13%.

5. Now we have two simple equations:

1) 33.39=100%

2) x=13%

where left sides of both of them have the same units, and both right sides have the same units, so we can do something like that:

33.39/x=100%/13%

6. Now we just have to solve the simple equation, and we will get the solution we are looking for.

7. Solution for what is 13% of 33.39

33.39/x=100/13

(33.39/x)*x=(100/13)*x - we multiply both sides of the equation by x

33.39=7.6923076923077*x - we divide both sides of the equation by (7.6923076923077) to get x

33.39/7.6923076923077=x

4.3407=x

x=4.3407

now we have:

13% of 33.39=4.3407

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Factor x3-2x2-9x+18 completely if(x+3) is a factor

Charra [1.4K]

Factor x^3 -2x^2-9x+18

= x^2(x - 2) - 9(x - 2)

= (x^2 - 9)(x -2)

= (x + 3 )(x - 3)(x - 2)

So (x+3) is a factor

6 0

3 years ago

Read 2 more answers

The attached Excel file 2013 NCAA BB Tournament shows the salaries paid to the coaches of 62 of the 68 teams in the 2013 NCAA ba

PSYCHO15rus [73]

The question is incomplete! Complete question along with answer and step by step explanation is provided below.

Question:

The attached Excel file 2013 NCAA BB Tournament shows the salaries paid to the coaches of 62 of the 68 teams in the 2013 NCAA basketball tournament (not all private schools report their coach's salaries). Consider these 62 salaries to be a sample from the population of salaries of all 346 NCAA Division I basketball coaches.

Question 1. Use the 62 salaries from the TOTAL PAY column to construct a 95% confidence interval for the mean salary of all basketball coaches in NCAA Division I.

xbar = $1,465,752

SD = $1,346,046.2

lower bound of confidence interval ________

upper bound of confidence interval _______

Question 2. Coach Mike Krzyzewski's high salary is an outlier and could be significantly affecting the confidence interval results. Remove Coach Krzyzewski's salary from the data and recalculate the 95% confidence interval using the remaining 61 salaries.

xbar = $1,371,191

SD = $1,130,666.5

lower bound of confidence interval _________

upper bound of confidence interval. ________

Answer:

Question 1:

lower bound of confidence interval = $1,124,027

upper bound of confidence interval = $1,807,477

Question 2:

lower bound of confidence interval = $1,081,512

upper bound of confidence interval = $1,660,870

Step-by-step explanation:

Question 1:

The sample mean salary of 62 couches is

$\bar{x} = 1,465,752$

The standard deviation of mean salary is

$s = 1,346,046.2$

The confidence interval for the mean salary of all basketball coaches is given by

$CI = \bar{x} \pm t_{\alpha/2}(\frac{s}{\sqrt{n} } )$

Where $\bar{x}$ is the sample mean, n is the sample size, s is the sample standard deviation and $t_{\alpha/2}$ is the t-score corresponding to a 95% confidence level.

The t-score corresponding to a 95% confidence level is

Significance level = α = 1 - 0.95 = 0.05/2 = 0.025

Degree of freedom = n - 1 = 62 - 1 = 61

From the t-table at α = 0.025 and DoF = 61

t-score = 1.999

So the required 95% confidence interval is

$CI = \bar{x} \pm t_{\alpha/2}(\frac{s}{\sqrt{n} } ) \\\\CI = 1,465,752 \pm 1.999 \cdot (\frac{1,346,046.2}{\sqrt{62} } ) \\\\CI = 1,465,752 \pm 1.999 \cdot (170948.04 ) \\\\CI = 1,465,752 \pm 341,725 \\\\LCI = 1,465,752 - 341,725 = 1,124,027 \\\\UCI = 1,465,752 + 341,725 = 1,807,477\\\\$

Question 2:

After removing the Coach Krzyzewski's salary from the data

The sample mean salary of 61 couches is

$\bar{x} = 1,371,191$

The standard deviation of the mean salary is

$s = 1,130,666.5$

The t-score corresponding to a 95% confidence level is

Significance level = α = 1 - 0.95 = 0.05/2 = 0.025

Degree of freedom = n - 1 = 61 - 1 = 60

From the t-table at α = 0.025 and DoF = 60

t-score = 2.001

So the required 95% confidence interval is

$CI = \bar{x} \pm t_{\alpha/2}(\frac{s}{\sqrt{n} } ) \\\\CI = 1,371,191 \pm 2.001 \cdot (\frac{1,130,666.5}{\sqrt{61} } ) \\\\CI = 1,371,191 \pm 2.001 \cdot (144767 ) \\\\CI = 1,371,191 \pm 289,678.8 \\\\LCI = 1,371,191 - 289,678.8 = 1,081,512 \\\\UCI = 1,371,191 + 289,678.8 = 1,660,870\\\\$

6 0

3 years ago

Write an equation to represent the total amount Shauna will owe her parents

Misha Larkins [42]

This would actually be a very broad question. So, when considering these kinds of questions, one thing that we would really want to consider would be the $(x)$ value in this case. We would want to find the amount, and also the terms of the expression.

So, let's suppose that the amount would be 200.

And let's say that Shauna makes 5 a week.

Then the expression would then look like $\boxed{5w=200}$

$(w)=weeks \\ \\ (5)= how \ much \ she \ makes \ in \ a \ week. \\ \\ so \ we \ do \ the \ amount \ she \ makes, \ and \ then \ \\multiplied \ by \ the \ amount \ of 
 \ weeks.$

I hope this would help you in your case of the problem! :)

5 0

3 years ago

Six ounces is what percent of a pound?

baherus [9]

Answer:

37.5%

Step-by-step explanation:

If you take 6 and divide it by 16, you will get 0.375. You then have to move the decimal two places to the left to get the percentage.

8 0

3 years ago