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Ray Of Light [21]
3 years ago
5

Is 2000 1 tenth of 200?

Mathematics
1 answer:
Iteru [2.4K]3 years ago
6 0

Answer:No

Step-by-step explanation:200 is 1 tenth of 2000 because 200 can go into 2000 10 times exactly. If you want to think about it this way 200 times 10 equals 2000

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How do you find the volume in cubic meters
jok3333 [9.3K]

Answer:

The answer is below:

Step-by-step explanation:

To calculate a volume in cubic meters, start by measuring your space. When measuring, find the length, width, and height of the space in meters. Next, multiply the three measurements together to find the volume in cubic meters. It's as easy as that!

You can tell me the length, width,and height and I can do it for you if you don't understand?

4 0
4 years ago
Read 2 more answers
9) Three times a number added to 12 gives -6. Find the number.​
KatRina [158]

Answer:

The number is -6.

Step-by-step explanation:

Variable x = a number

Set up an equation:

3x + 12 = -6

Isolate variable x:

3x = -18

x = -6

Check your work:

3(-6) + 12 = -6

-18 + 12 = -6

-6 = -6

Correct!

7 0
3 years ago
Read 2 more answers
Terry evaluates 6 divided by 1/8 using multiplication expression
Volgvan

what is way two get to the south pole.

6 0
3 years ago
I need help please with step by step it would help me a lot
pav-90 [236]

Answer:

Domain: (-infinity, +infinity) since you can pick any x values.

Range: [0, +infinity) since it does not go below the x axis.

Step-by-step explanation:

The graph is a parabola given by y=x^2

lets pick a few x values:

x = 1 gives us y = 1^2, which = 1

x = -1 gives us y = (-1)^2, which = 1

The parabola's domain is any x value as it extends to infinity.

For its range, you can see that it does not go below the x axis at x = 0. Therefore, the range of the parabola is from [0, infinity]

4 0
3 years ago
Suppose you are investigating the relationship between two variables, traffic flow and expected lead content, where traffic flow
prisoha [69]

Answer:

The answers is " Option B".

Step-by-step explanation:

CI=\hat{Y}\pm t_{Critical}\times S_{e}

Where,

\hat{Y}= predicted value of lead content when traffic flow is 15.

\to df=n-1=8-1=7

 95\% \ CI\  is\  (463.5, 596.3) \\\\\hat{Y}=\frac{(463.5+596.3)}{2}\\\\

     =\frac{1059.8}{2}\\\\=529.9

Calculating thet-critical valuet_{ \{\frac{\alpha}{2},\ df \}}=-2.365

The lower predicted value =529.9-2.365(Se)

463.5=529.9-2.365(Se)\\\\529.9-463.5=2.365(Se)\\\\66.4=2.365(Se)\\\\Se=\frac{66.4}{2.365} \\\\Se=28.076

When 99\% of CI use as the expected lead content: \to 529.9\pm t_{0.005,7}\times 28.076 \\\\=(529.9 \pm 3.499 \times 28.076)\\\\=(529.9 \pm 98.238)\\\\=(529.9-98.238, 529.9+98.238)\\\\=(431.662, 628.138)\\\\=(431.6, 628.1)

8 0
3 years ago
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