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Ray Of Light [21]
3 years ago
5

Is 2000 1 tenth of 200?

Mathematics
1 answer:
Iteru [2.4K]3 years ago
6 0

Answer:No

Step-by-step explanation:200 is 1 tenth of 2000 because 200 can go into 2000 10 times exactly. If you want to think about it this way 200 times 10 equals 2000

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joanna split three pitchers of water equally among her eight plants.what fraction of a pitcher did each plant get
Valentin [98]

Answer: \dfrac{3}{8}

Step-by-step explanation:

Given : Joanna split three pitchers of water equally among her eight plants.

i.e. The total number of pitcher plants = 8

The number of pitcher plants split by Joanna = 3

Then , the fraction of a pitcher did each plant get is given by :-

\dfrac{\text{No. of plants splits}}{\text{Total number of plants}}\\\\=\dfrac{3}{8}

Hence, the fraction of a pitcher did each plant get = \dfrac{3}{8}

4 0
3 years ago
Which facts could be applied to simplify this expression? Check all that apply.
tensa zangetsu [6.8K]

Answer:

The answer is B, C, and D. Like terms are terms with all the same variable, so 5x and -x are like terms.

C is correct. If we add -x to 5x, we get 4x. The other numbers remain unchanged because they have no like terms.

D is correct. Applying the rule of like terms, which is that like terms are numbers with the same variable, only add together numbers with the same variable.

6 0
3 years ago
In an intro stats class, 57% percent of students eat breakfast in the morning and 80% of students floss their teeth. Forty-six p
WINSTONCH [101]

Answer: B. 11%

Step-by-step explanation:

Let A = Event that students eat breakfast in the morning.

B= Event that students floss their teeth.

We are given P(A)=57%=0.57

P(B)=80%=0.80

P(A∩B) = 46% =0.46

Now, the probability that a student from this class eats break feast but does not floss their teeth :-

P(A-B)=P(A)-P(A\cap B)\\\\ = 0.57-0.46=0.11=11\%

Hence, the probability that a student from this class eats break feast but does not floss their teeth= 11%

3 0
3 years ago
Which are the solutions of x2 = –11x + 4?
Zarrin [17]

For this case we have the following polynomial:

x ^ 2 = -11x + 4

Rewriting the polynomial we have:

x ^ 2 + 11x - 4 = 0

From here, we can solve the polynomial using the quadratic equation

We have then:

x=\frac{-b+/-\sqrt{b^2-4ac}}{2a}

x=\frac{-11+/-\sqrt{11^2-4(1)(-4)}}{2(1)}

x=\frac{-11+/-\sqrt{11^2+16}}{2}

x=\frac{-11+/-\sqrt{121+16}}{2}

x=\frac{-11+/-\sqrt{137}}{2}

Therefore, the solutions are:

x=\frac{-11+\sqrt{137}}{2}

x=\frac{-11-\sqrt{137}}{2}



5 0
4 years ago
Read 2 more answers
Determine the digits of Q from these clues.
Maru [420]
Q=3456 is the correct answer to your question.
6 0
3 years ago
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