I'm not sure about what exactly your teacher is looking for, but the actual congruency conjecture you would use is:

(angle symbol) 1 (congruency symbol) (angle symbol) 8 - Because they are alternate exterior angles

8 0

3 years ago

GE = 3x - 11 FD = 2.x Find GE<br>Can someone help me??

11Alexandr11 [23.1K]

Answer:

Step-by-step explanation:

Given the following

GE = 3x - 11 FD = 2x

Let us assume GE is parallel to FD, hence GE = FD

3x - 11 = 2x

3x - 2x = 0+11

x = 11

Get GE

GE = 3x - 11

GE = 3(11)-11

GE= 33 - 11

GE = 22

Hence the length of GE is 22

3 0

2 years ago

plain why the function is discontinuous at the given number a. (Select all that apply.) f(x) = x2 − 2x x2 − 4 if x ≠ 2 1 if x =

ElenaW [278]

Answer with Step-by-step explanation:

We are given that

$f(x)=\left\{\begin{matrix}\dfrac{x^2-2x}{x^2-4}&,if\ \ x\neq 2 \\ 1&,if\ \ x=2\end{matrix}\right.$

We have to explain that why the function is discontinuous at x=2

We know that if function is continuous at x=a then LHL=RHL=f(a).

$f(x)=\frac{x(x-2)}{(x+2)(x-2)}=\frac{x}{x+2}$

LHL=Left hand limit when x <2

Substitute x=2-h

where h is small positive value >0

$\lim_{h\rightarrow 0}f(x)=\lim_{h\rightarrow 0}\frac{2-h}{2-h+2}$

$\lim_{h\rightarrow 0}\frac{2-h}{4-h}=\frac{2}{4}=\frac{1}{2}$

Right hand limit =RHL when x> 2

Substitute

x=2+h

$\lim_{h\rightarrow 0}f(x)=\lim_{h\rightarrow 0}\frac{2+h}{2+h+2}=\lim_{h\rightarrow 0}\frac{2+h}{4+h}$

$=\frac{2}{4}=\frac{1}{2}$

LHL=RHL= $\frac{1}{2}$

f(2)=1

$LHL=RHL\neq f(2)$

Hence, function is discontinuous at x=2

4 0

3 years ago