Answer:
a) the average CPI for machine M1 = 1.6
the average CPI for machine M2 = 2.5
b) M1 implementation is faster.
c) the clock cycles required for both processors.52.6*10^6.
Explanation:
(a)
The average CPI for M1 = 0.6 x 1 + 0.3 x 2 + 0.1 x 4
= 1.6
The average CPI for M2 = 0.6 x 2 + 0.3 x 3 + 0.1 x 4
= 2.5
(b)
The average MIPS rate is calculated as: Clock Rate/ averageCPI x 10^6
Given 80MHz = 80 * 10^6
The average MIPS ratings for M1 = 80 x 10^6 / 1.6 x 10^6
= 50
Given 100MHz = 100 * 10^6
The average MIPS ratings for M2 = 100 x 10^6 / 2.5 x 10^6
= 40
c)
Machine M2 has a smaller MIPS rating
Changing instruction set A from 2 to 1
The CPI will be increased to 1.9 (1*.6+3*.3+4*.1)
and hence MIPS Rating will now be (100/1.9)*10^6 = 52.6*10^6.
Answer:
public class LabProgram {
public static void main(String[] args) {
System.out.println("Hello World!"); } }
Explanation:
In this statement: System.out.println
System is a class in JAVA language package
out is a member of class System
println() is a functionT to print or display message to a console or file
So the message to print here is Hello World!
Now this statement System.out.println prints the message "Hello World!" passed in the argument.
Hence this statement as a whole displays the message Hello World! on the output screen.
Portrait, as well as 100 percent scale.
The technology is being used when you are sent an email saying you can track your package is known to be a scan code.
<h3>What are code-scanning technology?</h3>
This is known to be called a barcode reader or simply say a barcode scanner.
It is seen as a kind of an optical scanner that tends to read printed barcodes, as well as be able to decode the data that are found in the barcode and transmit the data to a computer.
Hence, The technology is being used when you are sent an email saying you can track your package is known to be a scan code.
Learn more about scan code from
brainly.com/question/24937533
#SPJ1
Answer:
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