Hi
f(x) = g(x) if -x²+3x-2 - ( -x+1) = 0
-x² +3x-2 +x-1 = 0
-x² +4x -3 = 0
To solve, tou have to use the general method of resolution of a quadratic fonction.
To determine if it's has a solution in R, let's calculate Δ
Δ = (4)² - 4 * (1) *(-3)
Δ = 16 +12
Δ= 28
as Δ≥ 0 so the function allow two solution within R
so S 1 = ( -4 +√28) / 2 S 2 = (-4 -√28 ) /2
S1 = ( -4 + 2√7) /2 S2 = (-4 - 2√7) /2
S1 = (2 (-2 +√7) /2 S2 2 (-2 -√7) /2
S1 = -2 +√7 S2 = -2 -√7
So the two function are equal twice. one for x = -2 +√7 and second x = -2-√7
Answer: $200
Explanation:
The employee pays $172.50 and he got 25% employee discount.
If the cost is $100, he pays $(100 - 25) = $75.
So, employee pays =
100
75
⋅
172.50
= $230.00.
Again, price was increased by 15% last year. So whose cost is $100
is sold by $(100+15) = $115.
When sell price is $115, then cost price is $100. Then,
when sell price is $230, then cost price is
100
115
⋅
230
= $200.
Answer:
As x → -∞, f(x) → 0.5; as x → ∞, f(x) → 0.5
Step-by-step explanation:
Given function:
<u>Asymptote</u>: a line that the curve gets infinitely close to, but never touches.
As the degrees of the numerator and denominator of the given function are equal, there is a horizontal asymptote at 
(where a is the leading coefficient of the numerator, and b is the leading coefficient of the denominator). This is the end behavior.
This is because as 
the -7 of the numerator and the +8 of the denominator become negligible. Therefore, we are left with:
Therefore:
