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wariber [46]
3 years ago
9

Find the rate of change: You burn 400 calories in one hour and you burn 1200 calories in 3 hours.

Mathematics
1 answer:
Harman [31]3 years ago
5 0
There is no rate of change, they both represent you burning 400 calories per hour.
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32 over x = -2 what is X
Contact [7]

Answer:

x+-16

Step-by-step explanation:

4 0
4 years ago
Suppose r(t) = (et cos t)i + (et sin t)j. Show that the angle between r and a never changes. What is the angle?
tatyana61 [14]

Answer:

Angle = Ф = cos^{-1}(0) = 0

Hence, it is proved that angle between position vector r and acceleration vector a = 0 and is it never changes.

Step-by-step explanation:

Given vector r(t) = e^{t}cost i + e^{t}sint j

As we know that,

velocity vector = v = \frac{dr}{dt}

Implies that

velocity vector = (e^{t} cost - e^{t} sint)i + (e^{t} sint - e^{t}cost )j

As acceleration is velocity over time so:

acceleration vector = a = \frac{dv}{dt}

Implies that

vector a =

(e^{t}cost - e^{t}sint - e^{t}sint - e^{t}cost )i + ( e^{t}sint + e^{t}cost + e^{t}cost - e^{t}sint )j

vector a = (-2e^{t}sint) i + ( 2e^{t}cost)j

Now scalar product of position vector r and acceleration vector a:

r. a = . \\

r.a = -2e^{2t}sintcost + 2e^{2t}sintcost

r.a = 0

Now, for angle between position vector r and acceleration vector a is given by:

cosФ = \frac{r.a}{|r|.|a|} = \frac{0}{|r|.|a|} = 0

Ф = cos^{-1}(0) = 0

Hence, it is proved that angle between position vector r and acceleration vector a = 0 and is it never changes.

4 0
3 years ago
Evaluate the expression 5(m-2) + 10w when m = 8.4 and w= 1.25
Lina20 [59]

Hey there!

5(m - 2) + 2w

= 5(8.4 - 2) + 10(1.25)

= 5(8.4) + 5(-2) + 10(1.25)

= 42 - 10 + 10(1.25)

= 32 + 12.50

≈ 32 + 12.5

= 44.50

≈ 44.5


Thus, your answer is: 44.5


Good luck on your assignment & enjoy your day!


~Amphitrite1040:)

5 0
2 years ago
(1+5 to the 2)−16 1 over 2 to the 3
Ludmilka [50]

Answer:

5/4

Step-by-step explanation:

I think this makes sense, if this is what ur asking for.

6 0
3 years ago
Read 2 more answers
Which expression is equivalent to (StartFraction a Superscript negative 8 Baseline b Over a Superscript negative 5 Baseline b cu
Eddi Din [679]

Answer:

its A, a^9 b^6

Step-by-step explanation:

right on edge 2020

8 0
3 years ago
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