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3 years ago

Write a brief explanation on how to simplify radicals

Mathematics

1 answer:

MrMuchimi3 years ago

5 0

2 ways: make a little divide tree based on how many times you can divide it. Like you have sqrt88 you know it can divide by 2. So its 2 and 44, and 44 can be broken to 2 and 22, then 2 and 11. 11 can’t be divided anymore.

Now choose numbers that are the same and pair them together. These go outside the radicand. You had three 2’s and one 11. So a 2 would go on the outside and the remaining 2 and 11 would be multiplied leaved 2sqrt22.

Another way is to divide by the highest squared number. Taking sqrt88 again. 4 would be the highest squared number. So 88 would be 4 and 22, then 2 and 11. Since you have a 4 which is a perfect square you put that squareroot outside. The inside would remain the same because it wouldn’t break down into perfect squares or pairs anymore. So that would be 2sqrt22.

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Answer:

Step-by-step explanation:

The easiest way is to substitute 8 for x in the first equation,

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3 years ago

Each bisect cost 5$ how many bisected can be bought with 285$

Alika [10]

285$ divided by 5$ = 57, 57 would be the correct answer.

3 0

3 years ago

Read 2 more answers

At the end of the current year, Accounts Receivable has a balance of $4,375,000; Allowance for Doubtful Accounts has a debit bal

Advocard [28]

Answer:

$226,300

Step-by-step explanation:

Given Allowance for Doubtful Accounts is estimated as $205,000 and Allowance for Doubtful Accounts has a debit balance of $21,300

#The amount of the adjusting entry for uncollectible accounts is calculated as below:

$Adjustment \ Cost=Allowance\ Doubtful\ Accounts +Doubtful \ Accounts \ Debit \ Balance\\\\=205000+21300\\\\\$226,300$

Hence, the amount of the adjusting entry for uncollectible accounts is $226,300

8 0

3 years ago

The sum of the diagonals of a rhombus is 5√2.

Alex

Greetings!
Let ABCD be a rhombus
AC + BD = 5√2 cm

Area of ABCD = Ar△ABD + Ar △BCD
$= \frac{1}{2} \times BD \times AO + \frac{1}{2} \times BD \times OC$
$= \frac{1}{2} BD (AO + OC)$
$\frac{1}{2} BD \times AC$

$So, \frac{ BD \times AC}{2} = 4 \: cm {}^{2}$
$BD \times AC = 8$
$Now, AC + \: BD = 5 \sqrt{2}$

Squaring both sides, we get
$AC {}^{2} + BD {}^{2} + 2 AC.BD =50$
$AC {}^{2} + BD {}^{2} + 2 \times 8 = 50$
$AC {}^{2} + BD {}^{2} = 50 - 16$
$AC {}^{2} + BD {}^{2} = 34$

In △AOB, we have
$OA {}^{2} + OB {}^{2} =AB {}^{2}$
$( \frac{ AC }{2} ) {}^{2} + ( \frac{ BD}{2} ) {}^{2} = AB {}^{2}$
$\frac{ AC {}^{2} } {4} + \frac{ BD {}^{2} }{4} = AB {}^{2}$
$AC {}^{2} + BD {}^{2} = 4 AB {}^{2}$
$34 = 4 AB {}^{2}$

Square rooting both sides
$\sqrt{34} = 2 AB$
$Perimeter = 4 \: AB \\ = 2 \times 2 \: AB \\ = 2 \: \times \sqrt{34 } \\ = 2 \sqrt{34 \: } units$ .

Hope it helps!

7 0

3 years ago

Help on this thx for helping if you did

vichka [17]

To evaluate two fractions being divided, you must turn the right fraction into a reciprocal. That means you must put the bottom number at the top and then put the top number on the bottom (you’re basically switching them).

8/13 / 3/2

Now, once you turned the other number into a reciprocal, you multiply across. The top number times the other top number and do this to the bottom numbers, too.

8/13 * 3/2 = 24/26

You found the answer, 24/26. But as you can see, it’s not one of the choices. That’s because you need to simplify.

24/26 / 2/2 = 12/13

12/13 is your answer, or choice C!

I hope this helped. Comment below if you have any questions.

6 0

3 years ago