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Jlenok [28]
3 years ago
8

Can someone solve this differentiation question.

Mathematics
2 answers:
Morgarella [4.7K]3 years ago
5 0
We clearly see on the graph that :
A. f is increasing on (2,6) and (8,10) (the derivative is >=0)
B. f is decreasing on (0,2) and (6,8) (the derivative is <=0)
C. f has two relative minima : one at x=2 and one at x=8 (the derivative changes signs there from negative to positive)
D. f has two relative maxima : one at x=6 and one at x=10(the derivative changes signs there from positive to negative)
E. f is concave up when f' is increasing i.e. on (0,4) and (7,9)
F. f is concave down when f' is decreasing i.e. on (4,7) and (9,10)
G. the points of inflexion of f are the points at which f' has an horizontal tangent, thus they are at x=4, x=7 and x=9
H. see the picture attached

sergij07 [2.7K]3 years ago
3 0

A).  The function is increasing where its derivative is positive.
Its derivative is positive from 2 to 6, and from 8 to 10.

B).  The function is decreasing where its derivative is negative.
Its derivative is negative from 0 to 2, and from 6 to 8.

C).  The function has a relative minimum where its derivative is zero
and changing from negative to positive.
Its derivative is zero and changing from negative to positive at 2 and 8.

D).  The function has a relative maximum where its derivative is zero
and changing from positive to negative.
Its derivative is zero and changing from positive to negative at 6 and 10.

E).  The function is concave up between consecutive relative maxima.
The interval between consecutive relative maxima is  6 < x < 10 .

F).  The function is concave down between consecutive relative minima.
The interval between consecutive relative minima is  2< x < 8 .

G).  The function has points of inflection where its second derivative is
zero, that is, where its first derivative is a relative minimum or a relative
maximum.
Its first derivative is a relative minimum or maximum at x =  0,  4,  7, and  9 .

H).  Good luck on the sketch !


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Water flows through a pipe at a rate of 490 milliliters every 6.5 hours. Express this rate of flow in fluid ounces per minute.
sergij07 [2.7K]

Answer:

0.42

Step-by-step explanation:

8 0
4 years ago
What is 9n=1(98-2n) equal to? Id really appreciate if you could answer both though
borishaifa [10]
N=32/3as a fraction alternative form is n=10.6
5 0
2 years ago
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Pie

Answer:

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Step-by-step explanation:

5 0
3 years ago
If f(x)= 3x squares +1 and g(x) =1-x what is the value of (f-g)(2)
ZanzabumX [31]

Answer: (f-g)(2)=14

Step-by-step explanation:

(f – g) (-2) means the same as subtracting f(2) and g(2). Since we are given f(x) and g(x), we can use them to solve. There are two ways to solve. One is to find f(2) and g(2), and then subtract them. Another way is to do (f-g)(x), then plug in x=2. I will show both methods.

Method 1

f(2)=3(2)²+1                                [exponent]

f(2)=3(4)+1                                  [multiply]

f(2)=12+1                                     [add]

f(2)=13

g(2)=1-(2)                                    [subtract]

g(2)=-1                  

(f-g)(2)=13-(-1)                            [subtract f(2) and g(2)]

(f-g)(2)=14

--------------------------------------------------------------------------------------------------------

Method 2

(f-g)(x)=3x²+1-(1-x)                     [distribute -1]

(f-g)(x)=3x²+1-1+x                      [combine like terms]

(f-g)(x)=3x²+x

(f-g)(2)=3(2)²+2                         [plug in x=2, exponent]

(f-g)(2)=3(4)+2                           [multiply]

(f-g)(2)=12+2                             [add]

(f-g)(2)=14

--------------------------------------------------------------------------------------------------------

Now, we know that (f-g)(2)=14. We confirmed this with both methods.

8 0
4 years ago
I need help with this! Quick ASAP?
sp2606 [1]

Answer:

a) F

b) B, E, D

Step-by-step explanation:

a) The segment with the greatest gradient has the largest change in y-values per unit change in x-values

From the given option, the rate of change of the <em>y </em>to the<em> </em>x-values of B = the gradient = (4 units)/(2 units) = 2

The gradient of F = (-3units)/(1 unit) = -3

The gradient of A = 4/4 = 1

The gradient of C = -2/5

The gradient of D = 2/6 = 1/3

The gradient of E = 3/4

The segment with the greatest gradient is F

b) The steepest segment has the higher gradient

From their calculated we have;

The gradient of segment B = 2 therefore, B is steeper than E that has a gradient of 3/4, and E is steeper than D, as the gradient of D = 1/3

Therefore, we have;

B, E, D.

6 0
3 years ago
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