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3 years ago

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ACCORDING TO A NEW YORK TIMES ARTICLE IN 2009 THE AVERAGE SELLING PRICE OF AN LCD TV WAS $700 WHAT WOULD BE THE COST OF THAT SAM

E TV 2016 DOLLARS

1 answer:

poizon [28]3 years ago

6 0

Step-by-step explanation:

Answer:

$2,500

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DO NOT POST UNUSEFUL ANSWERS! Serious answers only! A softball has a circumference of 12 inches. What is the softballs approxima

xxMikexx [17]

Formula for volume of a sphere: V = (4 / 3)(pi)(r^3)

Formula for circumference: C = (pi)(2r)

Solving for radius using circumference formula:

12 = (pi)(2r)

2r = 12 / pi

r = 12 / 2pi

Solving for volume:

V = (4 / 3)(pi)((12 / (2pi))^3)

Plug into calculator

V = 29.18 in^3

Hope this helps!! :)

4 0

3 years ago

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What is 20 over 3 divided into its simplest form?

marin [14]

Answer:

6 2/3

Step-by-step explanation:

3*6=18

20-18=2

6 2/3

8 0

3 years ago

Evaluate lim θ→0 sin(cos 8θ)/sec 5θ.

kenny6666 [7]

In this case, we are given with the expression <span>sin(cos 8θ)/sec 5θ and is asked to evaluate the expression with limit as theta approaches 0. In this case, we just substitute 0 to theta. cos 0 is equal to 1 hence sec 0 is also equal to 1. sin theta is equal to 0.0175. Answer os 0.0175.</span>

8 0

3 years ago

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Factorise the following expressions 5x^2-25xy

Natali [406]

Answer: 5x ( x - 5y )

Step-by-step explanation:

3 0

3 years ago

Evaluate the line integral, where c is the given curve. (x + 9y) dx + x2 dy, c c consists of line segments from (0, 0) to (9, 1)

viktelen [127]

$\displaystyle\int_C(x+9y)\,\mathrm dx+x^2\,\mathrm dy=\int_C\langle x+9y,x^2\rangle\cdot\underbrace{\langle\mathrm dx,\mathrm dy\rangle}_{\mathrm d\mathbf r}$

The first line segment can be parameterized by $\mathbf r_1(t)=\langle0,0\rangle(1-t)+\langle9,1\rangle t=\langle9t,t\rangle$ with $0\le t\le1$ . Denote this first segment by $C_1$ . Then

$\displaystyle\int_{C_1}\langle x+9y,x^2\rangle\cdot\mathbf dr_1=\int_{t=0}^{t=1}\langle9t+9t,81t^2\rangle\cdot\langle9,1\rangle\,\mathrm dt$
$=\displaystyle\int_0^1(162t+81t^2)\,\mathrm dt$
$=108$

The second line segment ( $C_2$ ) can be described by $\mathbf r_2(t)=\langle9,1\rangle(1-t)+\langle10,0\rangle t=\langle9+t,1-t\rangle$ , again with $0\le t\le1$ . Then

$\displaystyle\int_{C_2}\langle x+9y,x^2\rangle\cdot\mathrm d\mathbf r_2=\int_{t=0}^{t=1}\langle9+t+9-9t,(9+t)^2\rangle\cdot\langle1,-1\rangle\,\mathrm dt$
$=\displaystyle\int_0^1(18-8t-(9+t)^2)\,\mathrm dt$
$=-\dfrac{229}3$

Finally,

$\displaystyle\int_C(x+9y)\,\mathrm dx+x^2\,\mathrm dy=108-\dfrac{229}3=\dfrac{95}3$

5 0

3 years ago