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malfutka [58]
3 years ago
6

Elena’s bedroom door is 0.8 meters wide How wide should the door be on the drawing (in cm). Explain how you know. The scale is 1

cm = 50 cm
Mathematics
2 answers:
Vesnalui [34]3 years ago
8 0

Answer:

The door should be 1.6cm wide on the drawing.

Step-by-step explanation:

1 meter is 100 centimeters.

Elena's bedroom door is 80 centimeters wide.

To find how wide it should be on the drawing, divide by 50.

\frac{80}{50} = 1.6cm

The door should be 1.6cm wide on the drawing.

kvv77 [185]3 years ago
5 0
<h2>Answer:</h2>

The width of the door on the scale drawing in centimeters will be:

                       1.6 centimeter.

<h2>Step-by-step explanation:</h2>

It is given that:

Elena’s bedroom door is 0.8 m wide.

Also,the scale drawing is in the ratio of 1 to 50  i.e. 1:50

Now, we know that:

1 meter= 100 centimeter.

Hence,

0.8 meters= 80 centimeters.

This means that:

In order to find the width of  scale drawing:

We need to multiply original width of the door by 1/50.

i.e. we have:

80× 1/50 = 1.6 centimeter.

Hence, the width of the door on the scale drawing is: 1.6 centimeter.

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Answer:

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Step-by-step explanation:

Since 294 divided by 3 is 98, that means 294 is 3 times 98. So, we can say:

3 x 98 = 294

We can also say that 98 x 3 = 294 since it doesn't matter in which order you multiply.

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y =  \frac{1}{2} x + 1 \\

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2 \times y = 2 \times ( \frac{1}{2} x + 1) \\

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Subtract sides 2

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Yochanan walked from home to the bus stop at an average speed of 5 km / h. He immediately got on his school bus and traveled at
kari74 [83]

Answer: 5 km walking and 30 km by bus

Step-by-step explanation:

Yochanan walked from home to the bus stop at an average speed of 5 km / h. He immediately got on his school bus and traveled at an average speed of 60 km / h until he got to school. The total distance from his home to school is 35 km, and the entire trip took 1.5 hours. How many km did Yochanan cover by walking and how many did he cover by travelling on the bus?

walking - 5km/h                                         bus - 60km/h

distance walking - d₁                                 distance bus - d₂

time walking - t₁                                         time bus - t₂

d₁ + d₂ = 35

t₁ + t₂ = 1.5

v = d/t

vwalking = d₁/t₁

5 = d₁/t₁ ⇒ d₁ = 5t₁

vbus = d₂/t₂

60 = d₂/t₂ ⇒ d₂ = 60t₂

d₁ + d₂ = 35 ⇒ 5t₁ + 60t₂ = 35

_________________________

5t₁ + 60t₂ = 35

t₁ + t₂ = 1.5  (*-5)

5t₁ + 60t₂ = 35

-5t₁ -5t₂ = -7.5   (+)

__________________________

55t₂ = 27.5

t₂ = 27.5/55 = 0.5 h

t₁ + t₂ = 1.5 ⇒ t₁ = 1.5 - 0.5 = 1h

d₁ = 5t₁ ⇒ d₁ = 5.1 = 5 km

d₂ = 60t₂ ⇒ d₂ = 30.0.5 = 30 km

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34kurt

Answer:

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Step-by-step explanation:

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