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sveticcg [70]
3 years ago
12

Please answer this now with correct answer

Mathematics
1 answer:
lana66690 [7]3 years ago
7 0

Answer:

483.56 square milimeters

Step-by-step explanation:

In the above question, we obtain the following information:

Slant height = 15mm

Radius = 7mm

π = 3.14

Since we are given the slant height ,

the formula for surface area of a cone = πrl + πr²

= πr (l + r)

= 3.14 × 7(15 + 7)

= 3.14 × 7( 22)

= 21.98(22)

= 483.56 square milimeters

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What is 8% of 37...........
docker41 [41]

Answer:

2.96

Explanation:

37/x=100/8

(37/x)*x=(100/8)*x       - we multiply both sides of the equation by x

37=12.5*x       - we divide both sides of the equation by (12.5) to get x

37/12.5=x  

2.96=x  

x=2.96

7 0
3 years ago
Read 2 more answers
Suppose X, Y, and Z are random variables with the joint density function f(x, y, z) = Ce−(0.5x + 0.2y + 0.1z) if x ≥ 0, y ≥ 0, z
dexar [7]

Answer:

The value of the constant C is 0.01 .

Step-by-step explanation:

Given:

Suppose X, Y, and Z are random variables with the joint density function,

f(x,y,z) = \left \{ {{Ce^{-(0.5x + 0.2y + 0.1z)}; x,y,z\geq0  } \atop {0}; Otherwise} \right.

The value of constant C can be obtained as:

\int_x( {\int_y( {\int_z {f(x,y,z)} \, dz }) \, dy }) \, dx = 1

\int\limits^\infty_0 ({\int\limits^\infty_0 ({\int\limits^\infty_0 {Ce^{-(0.5x + 0.2y + 0.1z)} } \, dz }) \, dy } )\, dx = 1

C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0 {e^{-0.2y }(\int\limits^\infty_0 {e^{-0.1z} } \, dz  }) \, dy  }) \, dx = 1

C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0{e^{-0.2y}([\frac{-e^{-0.1z} }{0.1} ]\limits^\infty__0 }) \, dy  }) \, dx = 1

C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0 {e^{-0.2y}([\frac{-e^{-0.1(\infty)} }{0.1}+\frac{e^{-0.1(0)} }{0.1} ])  } \, dy  }) \, dx = 1

C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0 {e^{-0.2y}[0+\frac{1}{0.1}]  } \, dy  }) \, dx =1

10C\int\limits^\infty_0 {e^{-0.5x}([\frac{-e^{-0.2y} }{0.2}]^\infty__0  }) \, dx = 1

10C\int\limits^\infty_0 {e^{-0.5x}([\frac{-e^{-0.2(\infty)} }{0.2}+\frac{e^{-0.2(0)} }{0.2}]   } \, dx = 1

10C\int\limits^\infty_0 {e^{-0.5x}[0+\frac{1}{0.2}]  } \, dx = 1

50C([\frac{-e^{-0.5x} }{0.5}]^\infty__0}) = 1

50C[\frac{-e^{-0.5(\infty)} }{0.5} + \frac{-0.5(0)}{0.5}] =1

50C[0+\frac{1}{0.5} ] =1

100C = 1 ⇒ C = \frac{1}{100}

C = 0.01

3 0
3 years ago
Which of these lines is perpendicular to the line 3y = -2x + 5?
lesya [120]
Answer
Option C. 2y=3x+2
5 0
2 years ago
How do I solve this problem
Flura [38]
Shaded is 8.67
Circle A= pir^2
A= 3.14(4)(4)
A= 50.24

Hexagon
A= 1/2ap
1/2(4)(2sqrtof3)(6)
A= 41.569

50.24-41.569=8.671


3 0
3 years ago
Zero plus zero tolerance plzz tell me
Korolek [52]

Answer:

Это очень сложно но я говорю это 43168237978236472363429864236243616416891628438621348642198423864326742319743217828689642318794328643286468643267436436438643264366423674236742387423874236

I also speak English but that's no fun

4 0
3 years ago
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