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DanielleElmas [232]
3 years ago
5

What is the solution to equation? 4x+5=2x-3

Mathematics
1 answer:
Masteriza [31]3 years ago
8 0
4x - 2x = - 3 - 5
2x = - 8
x = - 4
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2 years ago
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3 years ago
The table represents a function.
yan [13]

Answer:

The table represents a function.

What is the value of f(-1)?

f(-1) = - 3

f(-1) = -1

f(-1) = 0

f(-1) = 6

Step-by-step explanation:

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2 years ago
The computer that controls a bank's automatic teller machine crashes a mean of 0.6 times per day. What is the probability that,
professor190 [17]

Answer:

0.2103 = 21.03% probability that, in any seven-day week, the computer will crash less than 3 times.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given interval.

Mean of 0.6 times a day

7 day week, so \mu = 7*0.6 = 4.2

What is the probability that, in any seven-day week, the computer will crash less than 3 times? Round your answer to four decimal places.

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)

In which

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-4.2}*(4.2)^{0}}{(0)!} = 0.0150

P(X = 1) = \frac{e^{-4.2}*(4.2)^{1}}{(1)!} = 0.0630

P(X = 2) = \frac{e^{-4.2}*(4.2)^{2}}{(2)!} = 0.1323

So

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0150 + 0.0630 + 0.1323 = 0.2103

0.2103 = 21.03% probability that, in any seven-day week, the computer will crash less than 3 times.

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2 years ago
The modified accelerated cost recovery system (MACRS):
ZanzabumX [31]

bahala kau ha ha. Matt wahak

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