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Jobisdone [24]
4 years ago
10

Find S12 for geometric series: (-7.5) + 15 + (-30) + ...

Mathematics
1 answer:
kolezko [41]4 years ago
5 0

Answer:

S12 for geometric series: (-7.5) + 15 + (-30) + ... would be: 10237.5

Step-by-step explanation:

Given the sequence to find the sum up-to 12 terms

(-7.5) + 15 + (-30) + ...

As we know that

A geometric sequence has a constant ratio 'r' and is defined by

a_n=a_1\cdot r^{n-1}

\mathrm{Compute\:the\:ratios\:of\:all\:the\:adjacent\:terms}:\quad \:r=\frac{a_{n+1}}{a_n}

\frac{15}{\left(-7.5\right)}=-2,\:\quad \frac{\left(-30\right)}{15}=-2

\mathrm{The\:ratio\:of\:all\:the\:adjacent\:terms\:is\:the\:same\:and\:equal\:to}

r=-2

\mathrm{The\:first\:element\:of\:the\:sequence\:is}

a_1=\left(-7.5\right)

a_n=a_1\cdot r^{n-1}

\mathrm{Therefore,\:the\:}n\mathrm{th\:term\:is\:computed\:by}\:

a_n=\left(-7.5\right)\left(-2\right)^{n-1}

a_n=-\left(-2\right)^{n-1}\cdot \:7.5

\mathrm{Geometric\:sequence\:sum\:formula:}

a_1\frac{1-r^n}{1-r}

\mathrm{Plug\:in\:the\:values:}

n=12,\:\spacea_1=\left(-7.5\right),\:\spacer=-2

  =\left(-7.5\right)\frac{1-\left(-2\right)^{12}}{1-\left(-2\right)}

  =-7.5\cdot \frac{1-\left(-2\right)^{12}}{1+2}

\mathrm{Multiply\:fractions}:\quad \:a\cdot \frac{b}{c}=\frac{a\:\cdot \:b}{c}

  =-\frac{-30712.5}{1+2}          ∵  \left(1-\left(-2\right)^{12}\right)\cdot \:7.5=-30712.5

 =-\frac{-30712.5}{3}

 =\frac{30712.5}{3}

 =10237.5

Thus, S12 for geometric series: (-7.5) + 15 + (-30) + ... would be: 10237.5        

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Answer:

m∠B = 69°

General Formulas and Concepts:

  • Order of Operations: BPEMDAS
  • Equality Properties
  • Complementary Angles add up to 90°

Step-by-step explanation:

<u>Step 1: Define</u>

m∠A = (x + 9)°

m∠B = (7x - 15)°

<u>Step 2: Set up equation</u>

m∠A + m∠B = 90°

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<u>Step 3: Solve for </u><em><u>x</u></em>

  1. Combine like terms:                    8x - 6 = 90
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<u>Step 4: Find m∠B</u>

  1. Define:                    m∠B = (7x - 15)°
  2. Substitute:              m∠B = (7(12) - 15)°
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The height of a tree trunk is 20 meters and the base diameter is 0.5 meter. a. The wood has a density of 380 kilograms per cubic
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Originally,
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d = 0.5 m, the diameter of the trunk

Because the density is 380 kg/m³, the mass of the trunk is
m= \frac{ \pi }{4} (0.5 \, m)^{2}(20 \, m)(380 \, \frac{kg}{m^{3}} ) = 1492.3 \, kg

Answer: 1492.3 kg

After one year:
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The tree grows by 0.2 m, s the new height is
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The increase in volume is
\Delta V=  \frac{ \pi }{4} (0.508 \, m)^{2}(20.2 \, m) -  \frac{ \pi }{4} (0.5 \, m)^{2}(20 \, m)  = 0.1672\, m^{3}

Answer: The volume produced  is 0.17 m³ (nearest hundredth) 
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