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kenny6666 [7]
3 years ago
13

What is 13 times0.53

Mathematics
1 answer:
sashaice [31]3 years ago
8 0
The answer is 6.89. hope this helps!
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A 12 ft ladder is leaning against a building. The ladder makes a 45 degree angle with the building how far up is the building do
Ghella [55]

Answer:

The ladder reach a height 8.485 ft.

Step-by-step explanation:

The ladder with the building made right angle triangle

The length of the ladder is the hypotenuse 12 ft.

The angle between the ladder and the building is 45°

The height of the ladder reach is the vertical side of the Δ

∴ h = 12 cos 45° = 6√2 = 8.485 ft.

4 0
3 years ago
-x^(2)-12=-87<br><br> Please explain your answer, and how I make the x positive
spayn [35]
Solve for x over the real numbers:
-x^2 - 12 = -87
Add 12 to both sides:
-x^2 = -75
Multiply both sides by -1:
x^2 = 75
Take the square root of both sides:
Answer:  x = 5 sqrt(3) or x = -5 sqrt(3)  both Answers are correct
7 0
3 years ago
Renna pushed the button for the elevator to go up, but it would not move. The weight limit for the elevator is 450 kilograms, bu
trasher [3.6K]
At least five passengers need to get off
5 0
3 years ago
Find the magnitude of −1−5i
ladessa [460]

The magnitude of -1-5i is √26.

<h3>What is the magnitude of -1-5i ?</h3>

Given the complex expression; -1 - 5i

To find the magnitude, we use the formula;

| a+bi | = √[ a² + b² ]

  • a = -1
  • b = -5

| a+bi | = √[ a² + b² ]

| -1-5i | = √[ (-1)² + (-5)² ]

| -1-5i | = √[ 1 + 25 ]

| -1-5i | = √26

Therefore, the magnitude of -1-5i is √26.

Learn more about magnitudes here: brainly.com/question/18152189

#SPJ1

8 0
2 years ago
Which of the following can be used to calculate the volume of water inside the fish bowl?
Lunna [17]

The volume of a sphere can be calculated as

V=\frac{4}{3}\pi r^3

Where r is the radius of the sphere

We want to calculate half of the volume, then we must divide that volume by 2

V^{\prime}=\frac{1}{2}\frac{4}{3}\pi r^3

Now we must find the radius of our sphere, the segment AB is the diameter of the sphere, and the radius is half od the diameter, then

r=\frac{AB}{2}=\frac{12}{2}=6

Let's put it into our equation

\begin{gathered} V^{\prime}=\frac{1}{2}\left(\frac{4}{3}\right)(\pi)(r)^3 \\  \\ V^{\prime}=\frac{1}{2}\left(\frac{4}{3}\right)(\pi)(6)^3 \end{gathered}

The problem says to use

\pi\approx\frac{22}{7}

Then

V^{\prime}=\frac{1}{2}\left(\frac{4}{3}\right)\left(\frac{22}{7}\right)(6)^3

Final answer:

The formula that can be used to calculate the volume of water inside the fish bowl is

V=\frac{1}{2}\left(\frac{4}{3}\right)\left(\frac{22}{7}\right)(6)^3

8 0
1 year ago
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