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Pachacha [2.7K]
3 years ago
11

You are given the dollar value of a product in 2012 and the rate at which the value of the product is expected to change during

the next 5 years. Write a linear equation that gives the dollar value V of the product in terms of the year t. (Let t = 0 represent 2010.)
Mathematics
1 answer:
Ray Of Light [21]3 years ago
3 0

Answer:

V=r*t+D-2*r

with

V= dollar value of the product

r= value's rate of change

t= time in years (where t=0 represents 2010)

D= dollar value of product in 2012

Step-by-step explanation:

A linear equation for V in terms of t will have the following form

V=r*t+C <em>(equation 1)</em>

where r will be the rate at which the value of the value of product is expected to change, V is the dollar value of the product at the year t (being t=0 for 2010) and C is a constant number which we should be able to find knowing the value of V at some point in time.

Let's call D the dollar value of the product in 2012, we can replace this value in <em>the equation 1</em> in order to find C

V=r*t+C <em>(equation 1)</em>

D=r*2+C

C=D-2*r

So the final equation would be

V=r*t+D-2*r

with

V= dollar value of the product

r= value's rate of change

t= time in years (where t=0 represents 2010)

D= dollar value of product in 2012

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A fruit company delivers its fruit in two types of boxes: large and small. Delivery of 8 large boxes and 4 small boxes has a tot
erma4kov [3.2K]

Answer:

x = 18.5 (large) , y = 6.25 (small)

Step-by-step explanation:

Let's start by assigning variables to each type of box.

The large box we will call "x"

The small box we will call "y"

We know that 8x + 4y = 173 (kilograms)

And 3x + 2y = 68 (kilograms)

Since we set up a system of equations, we can now use elimination, by multiplying the entire bottom equation by -2, to get rid of the "y" variable.

8x + 4y = 173

3x(-2) + 2y(-2) = 68(-2)

-6x + -4y = -136  (side note: notice how the "y"'s would cancel each other out because -4y + 4y equals 0)

Add equations together:

2x = 37

x= 18.5

Now that we have x, just substitute it into any of the equations to get y.

You will see that y = 6.25

Please mark this brainliest, and I hope this helps!

5 0
2 years ago
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Zigmanuir [339]

Answer:

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Step-by-step explanation:

GEMDAS

7 0
3 years ago
I don’t understand this equation please help me
Reika [66]

Answer:

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Step-by-step explanation:

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8 0
2 years ago
Assume that females have pulse rates that are normally distributed with a mean of μ=73.0 beats per minute and a standard deviati
Gennadij [26K]

Answer:

a. the probability that her pulse rate is less than 76 beats per minute is 0.5948

b. If 25 adult females are randomly​ selected,  the probability that they have pulse rates with a mean less than 76 beats per minute is 0.8849

c.   D. Since the original population has a normal​ distribution, the distribution of sample means is a normal distribution for any sample size.

Step-by-step explanation:

Given that:

Mean μ =73.0

Standard deviation σ =12.5

a. If 1 adult female is randomly​ selected, find the probability that her pulse rate is less than 76 beats per minute.

Let X represent the random variable that is normally distributed with a mean of 73.0 beats per minute and a standard deviation of 12.5 beats per minute.

Then : X \sim N ( μ = 73.0 , σ = 12.5)

The probability that her pulse rate is less than 76 beats per minute can be computed as:

P(X < 76) = P(\dfrac{X-\mu}{\sigma}< \dfrac{X-\mu}{\sigma})

P(X < 76) = P(\dfrac{76-\mu}{\sigma}< \dfrac{76-73}{12.5})

P(X < 76) = P(Z< \dfrac{3}{12.5})

P(X < 76) = P(Z< 0.24)

From the standard normal distribution tables,

P(X < 76) = 0.5948

Therefore , the probability that her pulse rate is less than 76 beats per minute is 0.5948

b.  If 25 adult females are randomly​ selected, find the probability that they have pulse rates with a mean less than 76 beats per minute.

now; we have a sample size n = 25

The probability can now be calculated as follows:

P(\overline X < 76) = P(\dfrac{\overline X-\mu}{\dfrac{\sigma}{\sqrt{n}}}< \dfrac{ \overline X-\mu}{\dfrac{\sigma}{\sqrt{n}}})

P( \overline X < 76) = P(\dfrac{76-\mu}{\dfrac{\sigma}{\sqrt{n}}}< \dfrac{76-73}{\dfrac{12.5}{\sqrt{25}}})

P( \overline X < 76) = P(Z< \dfrac{3}{\dfrac{12.5}{5}})

P( \overline X < 76) = P(Z< 1.2)

From the standard normal distribution tables,

P(\overline X < 76) = 0.8849

c. Why can the normal distribution be used in part​ (b), even though the sample size does not exceed​ 30?

In order to determine the probability in part (b);  the  normal distribution is perfect to be used here even when the sample size does not exceed 30.

Therefore option D is correct.

Since the original population has a normal distribution, the distribution of sample means is a normal distribution for any sample size.

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Which best describes the strength of the model? a weak positive correlation a strong positive correlation a weak negative correl
Akimi4 [234]

Correlation coefficient helps us to know how strong is the relation between two variables. The strength of the model is a strong positive correlation.

<h3>What is the correlation coefficient?</h3>

The correlation coefficient helps us to know how strong is the relation between two variables. Its value is always between +1 to -1, where, the numerical value shows how strong is the relation between them and, the '+' or '-' sign shows whether the relationship is positive or negative.

  • 1 indicates a strong positive relationship.
  • -1 indicates a strong negative relationship.
  • A result of zero indicates no relationship at all, therefore, independent variable.

Hence, the strength of the model is a strong positive correlation.

Learn more about Correlation Coefficients:

brainly.com/question/15353989

3 0
2 years ago
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