5 : 3
D1 = 3km = 3000 m (1km = 1000m)
D2 = 1800m
Ratio of D1:D2
=3000/1800
=1000/600 (dividing by 3)
=10/6 (dividing by 100)
=5/3 (dividing by 2)
= 5 : 3
Answer:
Step-by-step explanation:
In order to find an equation of a line with two given ordered pairs. We have to find a slope first which we can do by using the formula below.
m-term is defined as slope in y = mx+b form which is slope-intercept form.
Now we substitute these ordered pairs (x, y) in the formula.
After we calculate for slope, we substitute m-value in slope-intercept form. The slope-intercept form is
We already know m-value as we substitute it.
We are not done yet because we need to find the b-term which is our y-intercept. (Note that m-term is slope while b-term is y-intercept)
We can find the y-intercept by substituting either (-14,1) or (13,-2) in the equation. I will be using (13,-2) to substitute in the equation.
Finally, we know b-value. Then we substitute it in our equation.
Answer: A (1:2)
Step-by-step explanation:
Since there are 12 puppies total and 8 of the puppies are yellow labs, there must be 12 - 8 = 4 black labs. Now, the ratio of black labs to yellow labs is 4:8 because there are 4 black labs and 8 yellow labs. However, we can simplify this ratio by dividing the entire ratio by 4. In this case, we would get (4/4):(8/4), which simplifies to 1:2, which is the answer.
Answer: The slope of p is 1/3
Step-by-step explanation:
If the lines are perpendicular, this means they are opposite.
Thus, O is opposite P and since O = -3, P = 1/3
To simplify any fraction, look for a common factor in the top number
and the bottom number. If you find one, divide the top and bottom
both by their common factor. Eventually, you reach the point where
their only common factor is ' 1 ' ... that's when it's in simplest form.
4 and 10 both have 2 as a factor.
When you divide top and bottom both by 2, you have 2/5 .
This is the simplest form of 4/10 .
None of this has anything to do with mayflies. You can use the same
process to simplify fractions in ANY situation where fractions arise.
