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grandymaker [24]
4 years ago
15

Part 2: Identify the center and radius of each. Then sketch the graph.

Mathematics
1 answer:
Pavel [41]4 years ago
8 0

Answer:

See below for graphs

  1. (2, -3), r = 2 (blue)
  2. (-3, -1), r = 1 (green)
  3. (3, -1), r = 3 (purple)
  4. (4, 1), r = 3 (red)

Step-by-step explanation:

I like to solve a set of problems like this once, then use a calculator or spreadsheet to crunch the numbers.

We can start with the general form of the equation for a circle:

  x^2 +y^2 +ax +by +c = 0

Completing the square gives ...

  (x^2 +ax +(a/2)^2) +(y^2 +by +(b/2)^2) = (a/2)^2 +(b/2)^2 -c

  (x +(a/2))^2 +(y +(b/2))^2 = (a/2)^2 +(b/2)^2 -c

Comparing this to the standard form formula ...

  (x -h)^2 + (y -k)^2 = r^2

we see the relations are ...

  • h = -a/2
  • k = -b/2
  • r = √((a/2)² +(b/2)² -c)

where (h, k) is the center and r is the radius.

Then your circle centers and radii are ...

  1. (h, k) = (-(-4)/2, -6/2) = (2, -3); r = √(4+9-9) = 2
  2. (h, k) = (-6/2, -2/2) = (-3, -1); r = √(9+1-9) = 1
  3. (h, k) = (-(-6)/2, -2/2) = (3, -1); r = √(9+1-1) = 3
  4. (h, k) = (-(-8)/2, -(-2)/2) = (4, 1); r = √(16+1-8) = 3

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Answer:

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Step-by-step explanation:

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7 0
3 years ago
When Emily was born, she weighed 8.2 pounds. Two months later she weighed 10.15 pounds. How much weight did Emily gain in two mo
stiv31 [10]
Hey there! Hello!

The easiest way to solve this problem is by subtracting one value from the other. In order to find how much weight Emily gained in two months, we need to find the difference between her initial weight and how much she weighed at the end of two months:

10.15-8.20=1.95

You can see that I added a zero onto the end of the 8.2. This just evens out the amount of numbers and makes the problem easier to visualize while keeping the amount the same.

From the result of the problem, Emily gained 1.95 pounds in two months. 

I hope this helped you out! Feel free to ask me any additional questions if you have any. :-)
8 0
4 years ago
Read 2 more answers
A car travels at 49 km/hour how far does it travel in a 12 hour day​
marta [7]

Answer:   2.88 km.

Step-by-step explanation:

We will discuss here how to find the distance when speed and time are given.

When speed and time are given, the distance travelled is calculated by using the formula:

Distance = Speed × Time

The unit of time in speed should be the same as that of the given time.

Solved examples to calculate distance when speed and time are given:

1. How much distance will be covered in 5 hrs at a speed of 55 km per hour?

Solution:

Distance covered in 1 hour = 55 km.

We know, Distance = Speed × Time

Distance covered in 5 hrs = 55 × 5

                                  = 275 km.

Therefore, distance covered in 5 hrs = 275 km.

2. A bus travels at a speed of 45 km/hour. How far will it travel in 36 minutes?

Solution:

Speed = 45 km/hour

Time = 36 minutes

      = 36/60 Hour (Since we know, 1 hour = 60 minutes)

      = 3/5 hour

Distance = speed × time

           = 45 × (3/5) km

           = (45 × 3)/5 km

           = 27 km.

3. How much distance will be covered in 7 hrs at a speed of 62 km per hour?

Solution:

Distance covered in 1 hour = 62 km.

We know, Distance = Speed × Time

Distance covered in 7 hrs = 62 × 7

                                     = 434 km.

Therefore, distance covered in 7 hrs = 434 km.

4. Mike drives his car at a speed of 70 km per hour. How much distance will he cover in 3 hours 30 minutes?

Solution:

Speed of the car = 70 km/hr

Time taken         = 3 hours 30 minutes

                        = 3 ½ hours.

Distance covered in 1 hour = 70 km

Distance covered in 3 ½ hour = 70 × 3 ½ km

                                          = 70 × 7/2 km

                                          = 245 km.

5. How much distance will be covered in 1 ½ hour at a speed of 32 m per minute?

Solution:

[1 ½ hr = (60 + 30) minutes = 90 minutes].

Distance covered in 1 minute = 32 metres.

Distance covered in 90 minutes = 32 × 90 = 2880 m.

We know, 1 m = 1/1000 km.

                     = 2880/1000 km.

                     = 2.88 km.

Hope this helps!

5 0
2 years ago
1.)The angle θ lies in Quadrant IV. sinθ=−2/3 What is cosθ?
AveGali [126]

Answer:

1. From sin²θ +cos²θ =1 and sinθ=-2/3, we see that cosθ=√(1-sin²θ) or cosθ=√5/3, where the sign of cosine is positive as it is in Quadrant IV. x lies in 4th quadrant , cos x is +ve. , cos x = √5/3. Answer.

answer : cos x = √5/3

2.  4/3

3.  sin (- theta)  = - sin (x)        so sin x = 1/6

 tan = sin / cos   =  1/6  /  cos  =  - sqrt35/35     solve for cos

                        cos =  1/6 * (-35/sqrt35)

                       

                                  = -35 sqrt35 /210

answer : −35/√210

4. The cosine function is an even function, so cos(θ) = cos(-θ).

The relationship between sin(θ) and cos(θ) is sin(θ) = ±√(1 -cos(θ)^2)

For sin(θ) < 0 and cos(θ) = (√3)/4,  sin(θ) = -√(1 -3/16) = -√(13/16)

sin(θ) = -(√13)/4   For sin(θ) < 0 and cos(0) = √(3/4), ...

sin(θ) = -√(1 -3/4) = -√(1/4)       sin(θ) = -1/2

answer : -13/√4

5.  answer : tan^2 θ ⋅ cos^2 θ = 1 − cos^2 θ would be the first step

4 0
4 years ago
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