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Mariana [72]
3 years ago
6

Solve for X. It trust in you guys ❤️

Mathematics
1 answer:
xenn [34]3 years ago
6 0

Answer:

Step-by-step explanation:

Random

You might be interested in
Which model represents a fraction greater than Three-fifths? A circle divided into 5 equal parts. One part is shaded. A circle d
alexandr402 [8]

Answer: A circle divided into 10 equal parts with 8 parts shaded

Step-by-step explanation:

Alright, there are a lot of words here so lets write them down as fractions so its easier to compare.

A circle divided into 5 parts with 1 part shaded = 1/5

A circle divided into 10 parts with 5 parts shaded = 5/10

A circle divided into 6 parts with 2 parts shaded = 1/3

A circle divided into 10 parts with 8 parts shaded = 8/10

Okay so looking at this we can see that they don't have a common denominator so lets fix that

1/5 = 6/30

5/10 = 15/30

1/3 = 10/30

8/10 = 24/30

3/5 = 18/30

Now lets find which one is greater than 3/5

Only the 24/30 one is greater, and looking back that is the circle divided into 10 parts with 8 of them shaded.

4 0
3 years ago
Read 2 more answers
Find the value of x
Doss [256]

Answer:

x = 40

Step-by-step explanation:

The three angles in a triangle add to 180 degrees

x + 30 + (3x-10) = 180

Combine like terms

4x +20 = 180

Subtract 20 from each side

4x+20-20 = 180-20

4x= 160

Divide each side by 4

4x/4 =160/4

x = 40

8 0
3 years ago
Help me !! 10/7 x 9/8 7/9 x 8/10
FromTheMoon [43]

Answer:

Step-by-step explanation:

10/7 x 9/8 = 90/56 = 45/28.

7/9 x 8/10 = 56/90 = 28/45

If you want to multiply these, the answer is (28*45) / 28/45) = 1.

5 0
2 years ago
Read 2 more answers
Select the two values of x that are roots of this equation.<br> 2x+11x+15= 0
Amiraneli [1.4K]

Answer:

The roots of the equation are x=-3 and x=-2.5

Step-by-step explanation:

<u><em>The correct quadratic equation is</em></u>

2x^2+11x+15=0

we know that

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0 is equal to

x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}

in this problem we have

2x^{2} +11x+15=0  

so

a=2\\b=11\\c=15

substitute in the formula

x=\frac{-11(+/-)\sqrt{11^{2}-4(2)(15)}} {2(2)}

x=\frac{-11(+/-)\sqrt{121-120}} {4}

x=\frac{-11(+/-)\sqrt{1}} {4}

x=\frac{-11(+/-)1} {4}

x_1=\frac{-11(+)1}{4}=-2.5

x_2=\frac{-11(-)1}{4}=-3

therefore

The roots of the equation are x=-3 and x=-2.5

5 0
3 years ago
I rlly rlly need this badly, pls show work :(
elena55 [62]
1) 2x + 3y = 12 -> 3y = -2x +12 -> y = -2/3x + 4
2) 4y - 7x = 16 -> 4y = 7x + 16 -> y = 7/4x + 4
6 0
3 years ago
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