Write an expression that has three terms, two different variables, and one constant.

Two children, Ferdinand and Isabella, are playing with a water hose on a sunny summer day. Isabella is holding the hose in her h

wolverine [178]

Answer:

f = 0.84 or 84%

Step-by-step explanation:

Given:

- Original constant velocity of water v_o = 3.5 m/s

- The original diameter of the hose opening d_o = 1.5 cm

- The total vertical distance y(f) = 1.0 m

- The total range x(f) = 10.0 m

Find:

What fraction of the original area does Isabella has to reduce or pinch so the water can cover the entire range.

Solution:

- We will assume the flow of water as a stream of particles that follow a path of single point.

- Using second kinematic equation in the vertical direction and compute the time it takes the water to reach the ground:

y(t) = y(0) + v_y*t + 0.5*gt^2

Where, y(0) = v_y = 0,

1.0 = 0.5*g*t^2

t = sqrt ( 2*1 / 9.81 )

t = 0.4515 s

- Now we will use the second equation of motion for the x- direction motion:

x(t) = x(0) + v_x*t

Where, x(0) = 0,

10 = 0 + v_x*(0.4515)

v_x = 10 / 0.4515 = 22.1 m/s

- We have calculated the minimum velocity required to reach the range from isabella and ferdinand.

- We will use the continuity equation to compute the area required for the velocity calculated v_x = 22.1 m/s:

A_f*v_x = A_o*v_o

A_f = A_o*v_o / v_x

A_f = pi*0.015^2*3.5 / 4*22.1

A_f = 1.12 * 10^-4 m^2

- The fraction f of the reduction of area is:

f = (A_o - A_f) / A_o

f = (7.068*10^-8 - 1.12*10^-4) / (7.068*10^-8)

f = 0.84 or 84%

4 0

2 years ago

The amount of calories consumed by customers at the Chinese buffet is normally distributed with mean 2885 and standard deviation

aliina [53]

Answer:

a. X~N(2,885, 651)

b. 0.086291

c. 0.00058

d. 3213.10 calories

Step-by-step explanation:

a. -A normal distribution is expressed in the form X~N(mean, standard deviation).

-Let X a random variable denoting the number of calories consumed.

-X is a is a normally distributed random variable with mean 2885 and standard deviation 651.

-This distribution is expressed as X~N(2,885, 651)

b. The probability that less than 2000 calories are consumed is calculated using the formula:

$P(X$

#substitute the given values in the formula to solve for P:

$P(X$

Hence, the probability of consuming less than 2000 calories is 0.08691

c. The proportion of customers consuming more than 5000 calories is calculated as:

$P(X>x)=P(z>\frac{\bar X-\mu}{\sigma})\\\\=P(Z>\frac{5000-2885}{651})\\\\=P(z>3.2488)\\\\=1-0.99942\\\\=0.00058$

Hence, the proportion of customers consuming over 5000 calories is 0.00058

d. The least amount of calories to get the award is calculated as:

1% is equivalent to a z value of 0.50399.

-We equate this to the formula to solve for the mean consumption:

$0.01=P(z>\frac{\bar X-\mu}{\sigma})\\\\=P(z>\frac{\bar X-2885}{651})\\\\\1\%=0.50399 \\\\\frac{\bar X-2885}{651}=0.50399 \\\\\bar X=0.50399\times 651+2885\\\\=3213.09$

Hence, the least amount of calories consumed to qualify for the award is 3213.10 calories.

8 0

2 years ago

In Exercises 1-4, ill in the blank.

EleoNora [17]

1. Supplementary

2. Complementary

3. Adjacent angles

4. Vertically opposite angles

Hope it helps. Please mark brainliest.

4 0

2 years ago

Juan analyzes the amount of radioactive material remaining in a medical waste container over time. He writes the function f(x) =

forsale [732]

I believe this is right

5 0

2 years ago

Read 2 more answers

Evaluate he expression for x=4

hoa [83]

Answer:

41

Step-by-step explanation:

Step 1:

12x - 7 Equation

Step 2:

12 ( 4 ) - 7 Input x value

Step 3:

48 - 7 Multiply

Answer:

41 Subtract

Hope This Helps :)

8 0

2 years ago

Read 2 more answers