Answer:
The three quadratic equations are;
x² + 3 = 0
x² + 2·x + 1 = 0
x² + 3·x + 2 = 0
Step-by-step explanation:
1) A quadratic equation with no real solution is one with an imaginary solution such as one with a negative square root
We can write the quadratic equation as follows;
x² + 3 = 0
∴ x = √(-3) = √(-1) ×√3 = i·√(3)
Therefore, the equation f(x) = x² + 3, has no real root at f(x) = 0
2) A quadratic that has 1 real root is of the form;
(x + 1)² = 0
The root of the equation is x = -1 from (x + 1) = ((-1) + 1)² = 0²
Which gives;
(x + 1)² = (x + 1)·(x + 1) = x² + 2·x + 1 = 0
Therefore, the quadratic (x + 1)² = 0 has only one real root
3) A quadratic that has 2 real root is of the form;
(x + 1)·(x + 2) = 0
x² + x + 2·x + 2 = 0
x² + 3·x + 2 = 0
Therefore, the three quadratic equations are;
x² + 3 = 0
x² + 2·x + 1 = 0
x² + 3·x + 2 = 0
Answer:
120 customers on the 2nd day
Step-by-step explanation:
100/1ST DAY
120/2nd day
140/3rd day
160/ 4TH DAY
The product of A and B matrix will be option D; BA =
.
<h3>What is the multiplication of matrix?</h3>
If
and ![B = \left[\begin{array}{ccc}2&3&-5\\5&-4&2\\-1&-1&3\end{array}\right]](https://tex.z-dn.net/?f=B%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%263%26-5%5C%5C5%26-4%262%5C%5C-1%26-1%263%5Cend%7Barray%7D%5Cright%5D)
then,
BA = ![\left[\begin{array}{ccc}2&3&-5\\5&-4&2\\-1&-1&3\end{array}\right] \left[\begin{array}{ccc}-2&-4&2\\5&1&5\\-1&-3&-4\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%263%26-5%5C%5C5%26-4%262%5C%5C-1%26-1%263%5Cend%7Barray%7D%5Cright%5D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-2%26-4%262%5C%5C5%261%265%5C%5C-1%26-3%26-4%5Cend%7Barray%7D%5Cright%5D)
BA = ![\left[\begin{array}{ccc}16&10&39\\-32&-30&-18\\-6&-6&-19\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D16%2610%2639%5C%5C-32%26-30%26-18%5C%5C-6%26-6%26-19%5Cend%7Barray%7D%5Cright%5D)
Hence, the product of A and B matrix will be option D; BA =
.
Learn more about matrix here;
brainly.com/question/9967572
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Answer:
Graphs behave differently at various x-inter cepts. Sometimes the graph will cross over the x-axis at an intercept. Other times the graph will touch the x-axis and bounce off.
Suppose, for example, we graph the function. f(x) = (x+3)(x - 2)²(x+1)³.
Notice in the figure below that the behavior of the function at each of the x-intercepts is different.