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Grace [21]
3 years ago
8

If the discriminant is 22, do you have two real solutions?

Mathematics
2 answers:
labwork [276]3 years ago
8 0
Yes 2 real solutions
pentagon [3]3 years ago
7 0
If the discriminant is below 0, the solution is imaginary
If the discriminant is 0, there's exactly one real solution
If the discriminant is above 0, there are two real solutions.

Yes, you have two real solutions if you get 22 as discriminant.
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zavuch27 [327]

Answer:

56

Step-by-step explanation:

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3 years ago
Element X is a radioactive isotope such that every 5 years, its mass decreases by half.
Verdich [7]

Answer: 24 grams of element would remain.

Step-by-step explanation:

Exponential function for decay:

f(x)=Ab^{\frac{x}{n}} ....(i) , where A = initial value , b = decay factor, x = time , n= time per period

As per given,

A = 569 grams , b=\dfrac12

n= 5 years, t = 23 years

Put all values in (i) , we get

f(23)=590(\dfrac12)^{\frac{23}{5}}\\\\\\=590\times 0.0412346222117\\\\=24.3284271049\approx 24

Hence, after 23 years , 24 grams of element would remain.

6 0
3 years ago
How is the graph of the parent quadratic function transformed to produce the graph of y=-(2x+6) + 3?
Andrews [41]
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3 0
3 years ago
Read 2 more answers
The function h(t)=−16t(t−7) models the height of an object at any time t after it is launched, where t is measured in seconds. A
Kipish [7]

Answer:

2.65secs

Step-by-step explanation:

Give:

The function h(t)=−16t(t−7) models

the object will hit the ground at h= 0

h(t)=−16t(t−7)

0= -16t(t−7)

0= -16t^2 + 112

16t^2 = 112

t^2 = 7

t= √7

t=2.65secs

Hence, the object object hit the ground at 2.65secs

7 0
3 years ago
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