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2 years ago

11

The area of a square region is 169 m2 (square)

2 answers:

LUCKY_DIMON [66]2 years ago

4 0

Answer:

A. 13m

Step-by-step explanation:

To find the area of a square you multiply Length by the Height. Since squares have equal length sides the number has to be the same for the length and the height.

13 x 13 = 169

$\sqrt{169} = 13$

PilotLPTM [1.2K]2 years ago

4 0

Answer:

A. 13m

Step-by-step explanation:

Because it's a square, all sides will be the same length. And since you're looking at area in m², you can square root the area.

$\sqrt{169}$ =13

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If a plane can travel 500 miles per hour with the wind and 400 miles per hour against the wind, find the speed of the wind and t

OLga [1]

Wind speed is 50 mph

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3 years ago

What is a solution to the equation 3 / m + 3 - M / 3 - M equals m^2 + 9 / m^2-9?

Mnenie [13.5K]

Answer: Last option.

Step-by-step explanation:

Given the equation:

$\frac{3}{m+3}-\frac{m}{3-m}=\frac{m^2+9}{m^2-9}$

Follow these steps to solve it:

- Subtract the fractions on the left side of the equation:

$\frac{3(3-m)-m(m+3)}{(m+3)(3-m)}=\frac{m^2+9}{m^2-9}\\\\\frac{9-3m-m^2-3m}{(m+3)(3-m)}=\frac{m^2+9}{m^2-9}\\\\\frac{-m^2-6m+9}{(m+3)(3-m)}=\frac{m^2+9}{m^2-9}$

- Using the Difference of squares formula ( $a^2-b^2=(a+b)(a-b)$ ) we can simplify the denominator of the right side of the equation:

$\frac{-m^2-6m+9}{(m+3)(3-m)}=\frac{m^2+9}{(m+3)(m-3)}$

- Multiply both sides of the equation by $(m+3)(3-m)$ and simplify:

$\frac{(-m^2-6m+9)(m+3)(3-m)}{(m+3)(3-m)}=\frac{(m^2+9)(m+3)(3-m)}{(m+3)(m-3)}\\\\-m^2-6m+9=\frac{(m^2+9)(3-m)}{(m-3)}$

- Multiply both sides by $m-3$ :

$(-m^2-6m+9)(m-3)=\frac{(m^2+9)(3-m)(m-3)}{(m-3)}\\\\(-m^2-6m+9)(m-3)=(m^2+9)(3-m)$

- Apply Distributive property and simplify:

$(-m^2-6m+9)(m-3)=(m^2+9)(3-m)\\\\-m^3-6m^2+9m+3m^2+18m-27=3m^2+27-m^3-9m\\\\-m^3-3m^2+27m-27+m^3-3m^2+9m-27=0\\\\-6m^2+36m-54=0$

- Divide both sides of the equation by -6:

$\frac{-6m^2+36m-54}{-6}=\frac{0}{-6}\\\\m^2-6m+9=0$

- Factor the equation and solve for "m":

$(m-3)^2=0\\\\m=3$

In order to verify it, you must substitute $m=3$ into the equation and solve it:

$\frac{3}{3+3}-\frac{3}{3-3}=\frac{3^2+9}{3^2-9}\\\\\frac{3}{6}-\frac{3}{0}=\frac{18}{0}$

<em>NO SOLUTION</em>

7 0

2 years ago

Fill in the table using this function rule

marusya05 [52]

<h3>hello!</h3>

Plug in the values of x and solve for y:-

y=5+4x

y=5+4(4)

y=5+16

y=21

________________________________

y=5+4x

y=5+5(5)

y=5+20

y=25

_________________________________

y=5+4x

y=5+4(8)

y=5+32

y=37

___________________________________

y=5+4x

y=5+4(10)

y=5+40

y=45

__________________________________

<h3>note:-</h3>

Hope everything is clear; if you need any clarification/explanation, kindly let me know, and I will comment and/or edit my answer :)

8 0

2 years ago

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What are the excluded values?

OverLord2011 [107]

Answer:

c. x = -9.

Step-by-step explanation:

The excluded value is the value of x which gives a value of 0 to the denominator, so that value would be x = -9.

Note: (x - 7) / 0 is undefined.

7 0

3 years ago

What is the answer to 7b-b=-6

sergejj [24]

6b=-6
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3 0

3 years ago

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