The first part of the answer is 20x+9
Second part is 4a-6b
g(x) = 2x-6
f(x) = -4x +7
(g•f)(x) = g(f(x))
= 2(f(x)) - 6
= 2 ( -4x+7) -6
= -8x + 14 -6
= -8x +8
now
(g•f)(1) = -8(1) + 8= -8+8
= 0
so option a is answer
Write the coeeficientes of the polynomial in order:
| 1 - 5 6 - 30
|
|
|
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After some trials you probe with 5
| 1 - 5 6 - 30
|
|
5 | 5 0 30
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1 0 6 0 <---- residue
Given that the residue is 0, 5 is a root.
The quotient is x^2 + 6 = 0, which does not have a real root.
Therefore, 5 is the only root. You can prove it by solving the polynomial x^2 + 6 = 0.
1. 4x - 8 + 2x + (-5x) + x^2 - 3 = 4x - 8 + 2x - 5x + x^2 - 3...now, we just combine like terms....lets group them...it will be easier ...x^2 + (4x + 2x - 5x ) - 8 - 3 = x^2 + x - 11
2. 2x + 5x = 8x
3. 2r + 4 + 3x - 2 = 3x + 2r + (4 - 2) = 3x + 2r + 2
4. 3x - 2y - x + 5y = (3x - x) + (5y - 2y) = 2x + 3y
5. 2y^2 - 8y^3 + 5y - 5y^2 + 4y^3 = (4y^3 - 8y^3) + (2y^2 - 5y^2) + 5y =
-4y^3 - 3y^2 + 5y
Answer:
The zeros are 8 and -10, all u have to do is substitute x for those values, factor it, or graph it.