Consider the length of diagonal is 8.5 cm instead of 8.5 m because length of perpendiculars are in cm.
Given:
Length of the diagonal of a quadrilateral = 8.5 cm
Lengths of the perpendiculars dropped on it from the remaining opposite vertices are 3.5 cm and 4.5 cm.
To find:
The area of the quadrilateral.
Solution:
Diagonal divides the quadrilateral in 2 triangles. If diagonal is the base of both triangles then the lengths of the perpendiculars dropped on it from the remaining opposite vertices are heights of those triangles.
According to the question,
Triangle 1 : Base = 8.5 cm and Height = 3.5 cm
Triangle 2 : Base = 8.5 cm and Height = 4.5 cm
Area of a triangle is

Using this formula, we get


and


Now, area of the quadrilateral is



Therefore, the area of the quadrilateral is 34 cm².
Alright, so you can try to study hard and gain a passing grade (A+) for the other two quarters.
Answer:
Length is 90yards and width is 60yards
Step-by-step explanation:
Perimeter= 2( length+width)
let the width be x
then the length will be 30 + x
300 = 2(30+x+x)
150 = 30 + 2x
120= 2x
x = 120/2
x = 60 yards
length= 30+x
= 30 + 60
= 90yards
Answer: First add 5 to both sides
Answer:
5(4) + 5(8)
Step-by-step explanation:
Through destributive property, 5 is multiplied by both 4 and 8