A. 5 invitations
b. 15 invitations
Comment if you need me to explain it.
For a right triangle with legs legnth a and b and hyptonuse c
a^2+b^2=c^2
9 feet from base, that's one leg
wire is hypotnuse, it's 1 more than height on tree
c=b+1
so
9^2+b^2=(b+1)^2
81+b^2=b^2+2b+1
minus b^2+1 from both sides
80=2b
divide both sides by 2
40=b
c=b+1
c=40+1
c=41
legnth of wire is 41ft
Answer:
B
Step-by-step explanation:
- divide the given polygon into two (a square and a trapezium
- area of trapezium=1/2(a+b)×b 1/2(12+6)×12 ans 108square unit
- area of a square=s×s 12×12 =144square unit
- add 108+144=252square unit
Answer:
1001
Step-by-step explanation:
Answer:
The ribbon is 28.4 meters
Step-by-step explanation:
Given the box is 5m high, 6m long, and 8m wide,
we have a right angled triangle with hypotenuse = unknown, x, say
Opposite = 5m and 8m
Then, by Pythagoras theorem
x² = 5² + 8²
x² = 25 + 64
x² = 89
x = √89 ≈ 9.4m
The ribbon is now (5 + 6 + 8 + 9.4)m = 28.4m