Answer:
A) 1/(3x+1)
Step-by-step explanation:
(x+2)/(x³+2x²-9x-18)÷(3x+1)/(x²-9)
(x+2)/(x+2)(x+3)(x-3)÷(3x+1)/(x+3)(x-3)
since it’s dividing by a fraction, invert and multiply
(x+2)/(x+2)(x+3)(x-3) times (x+3)(x-3)/(3x+1)
The (x+2)’s cancel out.
The (x+3)’s cancel out.
The (x-3)’s cancel out.
You are left with 1/(3x+1)
Answer:
The maximum height of the projectile is 90 ft
Step-by-step explanation:
Here, we want to get the maximum height reached by the projectile
The answer here will be the y-coordinate value of the vertex form of the given equation
so firstly, we have to write the equation in the vertex form
We have this as;
y = -16t^2 + 64t + 26
That will be;
y = a(x-h)^2 + k
y = -16(x-2)^2 + 90
where the vertex of the equation is;
(-h,k)
K
in this case is 90 and thus, that is the maximum height of the projectile
Answer:
2nd one..
Step-by-step explanation:
but although all are wrongmm barnotation is not used
As soon as possible after the lecture
.2x.8=.16
2.4x.7=1.68
3.9x.4=1.56
.9x.1=.09
.2x1.5=.3
.6x.6=.36